问题
I am trying to make an object out of a paragraph that shows words with their frequencies.
var pattern = /\w+/g,
//the farsi paragraph
string = "من امروز در مورد مهر خروج مشمولین اطلاعات جدیدی از سفارت ایران در مالزی گرفتم",
matchedWords = string.match( pattern );
/* The Array.prototype.reduce method assists us in producing a single value from an
array. In this case, we're going to use it to output an object with results. */
var counts = matchedWords.reduce(function ( stats, word ) {
/* `stats` is the object that we'll be building up over time.
`word` is each individual entry in the `matchedWords` array */
if ( stats.hasOwnProperty( word ) ) {
/* `stats` already has an entry for the current `word`.
As a result, let's increment the count for that `word`. */
stats[ word ] = stats[ word ] + 1;
} else {
/* `stats` does not yet have an entry for the current `word`.
As a result, let's add a new entry, and set count to 1. */
stats[ word ] = 1;
}
/* Because we are building up `stats` over numerous iterations,
we need to return it for the next pass to modify it. */
return stats;
}, {})
var dict = []; // create an empty array
// this for loop makes a dictionary for you
for (i in counts){
dict.push({'text':i, "size": counts[i]});
};
/* lets print and see if you can solve your problem */
console.log( dict);
the code originally worked out for an English paragraph. However I need to use it for a Farsi one. I know that it should be something else instead of "/\w+/g" in:
var pattern = /\w+/g,
but I don't know what.
回答1:
In your regex use the variable for "any character but whitespace" that is \S.
Edit: whitespace is considered a newline, a tab and a space)
var pattern = /\S+/g,
//the farsi paragraph
string = "من امروز در مورد مهر خروج مشمولین اطلاعات جدیدی از سفارت ایران در مالزی گرفتم",
matchedWords = string.match( pattern );
/* The Array.prototype.reduce method assists us in producing a single value from an
array. In this case, we're going to use it to output an object with results. */
var counts = matchedWords.reduce(function ( stats, word ) {
/* `stats` is the object that we'll be building up over time.
`word` is each individual entry in the `matchedWords` array */
if ( stats.hasOwnProperty( word ) ) {
/* `stats` already has an entry for the current `word`.
As a result, let's increment the count for that `word`. */
stats[ word ] = stats[ word ] + 1;
} else {
/* `stats` does not yet have an entry for the current `word`.
As a result, let's add a new entry, and set count to 1. */
stats[ word ] = 1;
}
/* Because we are building up `stats` over numerous iterations,
we need to return it for the next pass to modify it. */
return stats;
}, {})
var dict = []; // create an empty array
// this for loop makes a dictionary for you
for (i in counts){
dict.push({'text':i, "size": counts[i]});
};
/* lets print and see if you can solve your problem */
console.log( dict);回答2:
To match any letter, you need to use an XRegExp package and the \pL Unicode property class:
var pattern = new XRegExp("[_\\pL\\pN]+", "g");
var s = "من امروز در مورد مهر خروج مشمولین اطلاعات جدیدی از سفارت ایران در مالزی گرفتم";
var matchedWords = s.match( pattern );
var counts = matchedWords.reduce(function ( stats, word ) {
if ( stats.hasOwnProperty( word ) ) {
stats[ word ] = stats[ word ] + 1;
} else {
stats[ word ] = 1;
}
return stats;
}, {})
var dict = [];
for (i in counts){
dict.push({'text':i, "size": counts[i]});
}
console.log(dict);<script src="https://cdnjs.cloudflare.com/ajax/libs/xregexp/3.2.0/xregexp-all.min.js"></script>The [_\\pL\\pN]+ pattern matches one or more underscores (_, I included it because \w in your original regex also matched _), Unicode letters (\pL) and digit (\pN).
To only count words made of letters, just use
var pattern = new XRegExp("\\pL+", "g");
回答3:
Why not just using split combined with reduce in your case? Example:
const p = 'من امروز در مورد مهر خروج مشمولین اطلاعات جدیدی از سفارت ایران در مالزی گرفتم';
const counted = p.split( ' ' ).reduce( ( collected, item ) => {
collected[ item ] = ( collected[ item ] || 0 ) + 1;
return collected;
}, { /* initial empty object */ } );
const dict = Object.keys( counted ).map( key => {
return {
text: key,
size: counted[ key ],
};
} );
console.log( 'در:', counted[ 'در' ] );
console.log( dict );It is way simpler and performs better. You could even leave out the const dict... part.
回答4:
You could use the JS equivalent for word and quantifier \w+
where this will match about 119,000 Unicode 9 word characters.
This includes all the non-letter, non-number, other word characters
like the underscore, for which there are about 1,100 of them.
Note - it runs very quick, however I would make this regex global and
compile it once for later use.
Also, this was generated from the ICU database, which gives a complete
sample of the word \w between U+000000 to U+10FFFF, from which this regex
is generated using the UCD Interface, in the RegexFormat app.
This is something that XRegExp can't do.
Demo:
https://regex101.com/r/sjLmMC/1
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来源：https://stackoverflow.com/questions/45847448/how-to-turn-a-persian-farsi-paragraph-into-its-list-of-words-in-javascript