问题
I have a .mat
file which I load using scipy
:
from oct2py import octave
import scipy.io as spio
matPath = "path/to/file.mat"
matFile = spio.loadmat(matPath)
I get a numpy array which I want to pass to octave function using oct2py
, like that:
aMatStruct = matFile["aMatStruct"]
result = octave.aMatFunction(aMatStruct)
But I get the following error:
oct2py.utils.Oct2PyError: Datatype not supported
It seems it's due to the array dtype
, which looks like: [('x', 'O'), ('y', 'O'), ('z', 'O')]
So I thought about changing it to 'S'
, 'U'
, or something that's supported.
- How can it be done?
- I couldn't find a supported dtype in the otc2py documentation. Any help on that?
- Is there a way to load the
.mat
file with another (supported) dtype? I looked here but couldn't find anything useful.
Note that inside aMatFunction
it uses aMatStruct
like that: x = aMatStruct.x
.
回答1:
Found a workaround!
I used the following script, which reconstructs python dictionaries from the loaded struct, which oct2py2
in turn interpret as matlab structs.
回答2:
I was going to suggest converting the resulting array to a valid dictionary but you beat me to it so I won't code it :p
However, the other, simpler solution I was going to suggest is that, since you're only using the struct within octave, you could just load it into its workspace and evaluate directly. i.e. the following works for me:
>>> octave.load("MyFile.mat")
>>> octave.eval("fieldnames(S)")
ans =
{
[1,1] = name
[2,1] = age
}
[u'name', u'age']
EDIT eh screw it, here's the python solution; I'd started it anyway :p
>>> from oct2py import octave
>>> from scipy.io import loadmat
>>> F = loadmat("/home/tasos/Desktop/MyFile.mat")
>>> M = F["S"] # the name of the struct variable I saved in the mat file
>>> M = M[0][0]
>>> D = {M.dtype.names[i]:M[i][0] for i in range(len(M))}
>>> out = octave.fieldnames(D); out
[u'age', u'name']
来源:https://stackoverflow.com/questions/39384998/change-dtype-data-type-fields-of-numpy-array