问题
I have initialised a datatable with json data on page ready. Now on click event i want to change the table data. When i use the delete(), error is thrown saying 'undefuned style' and the table object can still be seen in the page. Here is the code:
**JS : **
function createTable(obj){
var myTableDiv = document.getElementById("populate_table");
var table = document.createElement('TABLE');
table.id='dynamictable';
var header = table.createTHead();
var row = header.insertRow(0);
var cell = row.insertCell(0);
cell1 = row.insertCell(1);
cell2 = row.insertCell(2);
cell3 = row.insertCell(3);
cell4 = row.insertCell(4);
cell5 = row.insertCell(5);
cell6 = row.insertCell(6);
cell7 = row.insertCell(7);
cell8 = row.insertCell(8);
cell.innerHTML = "<b>Title</b>";
cell1.innerHTML = "<b>Qualificatoin</b>";
cell2.innerHTML = "<b>Salary</b>";
cell3.innerHTML = "<b>Company Name</b>";
cell4.innerHTML = "<b>Tags</b>";
cell5.innerHTML = "<b>Location</b>";
cell6.innerHTML = "<b>Experience</b>";
cell7.innerHTML = "<b>About Company</b>";
cell8.innerHTML = "<b>Apply Here</b>";
var tableBody = document.createElement('TBODY');
table.appendChild(tableBody);
console.log("json length : "+obj.length);
for (var i=0; i<obj.length; i++){
/*var tr = document.createElement('TR');
tableBody.appendChild(tr);
var td = document.createElement('TD');
//td.width='75';
td.appendChild(document.createTextNode("Cell " + i + "," + j));
tr.appendChild(td);*/
var btn = document.createElement("BUTTON");
var t = document.createTextNode("CLICK ME");
btn.appendChild(t);
btn.id='apply-button';
var input = document.createElement("input");
input.setAttribute("id",obj.firstName);
input.setAttribute("type", "hidden");
input.setAttribute("name", "jobID");
input.setAttribute("value", obj.firstName);
var rowCount = tableBody.getElementsByTagName("tr").length;
var row1 = tableBody.insertRow(rowCount);
row1.id="x";
var rowcell0=row1.insertCell(0);
var rowcell1=row1.insertCell(1);
var rowcell2=row1.insertCell(2);
var rowcell3=row1.insertCell(3);
var rowcell4=row1.insertCell(4);
rowcell4.id='doit';
var rowcell5=row1.insertCell(5);
var rowcell6=row1.insertCell(6);
var rowcell7=row1.insertCell(7);
var rowcell8=row1.insertCell(8);
var rowcell9=row1.insertCell(9);
rowcell0.innerHTML= obj[i].title;
rowcell1.innerHTML= obj[i].qualification;
rowcell2.innerHTML= obj[i].salary;
rowcell3.innerHTML=obj[i].companyName;
rowcell4.innerHTML=obj[i].tags;
rowcell5.innerHTML=obj[i].location;
rowcell6.innerHTML=obj[i].experience;
rowcell7.innerHTML=obj[i].aboutCompany;
//rowcell8.innerHTML=obj[i].firstName;
rowcell9.innerHTML=obj[i].jobID;
//document.getElementById("doit").appendChild(btn);
}if(data_table==="flag"){ myTableDiv.appendChild(table);
data_table=$('#dynamictable').DataTable({
"paging" : true,
"ordering" : true,
"info" : false,
"searching" : true,
"bDestroy" : true,
"columnDefs": [
{
"targets": [ 9 ],
"visible": false,
"searchable": false
},{
"targets": 8,
"data": null,
"defaultContent": "<button>Apply</button>"
}
]
});
}
else{
data_table.destroy();
// $('#dynamictable').empty();
}
$('#dynamictable tbody').on( 'click', 'button', function () {
var data = data_table.row( $(this).parents('tr') ).data();
var formData=data[9];
console.log("The data : "+data[9]);
$.ajax({
type : "GET",
url : "apply",
data:"jobID="+formData,
dataType : "text",
async: true,
success : function(response) {
console.log("The response : "+response);
}
});
});
};});
回答1:
For dataTables I don't use delete(). This is the code that I use when deleting a selected row:
$("#delete_button").on('click', function(data) {
data_table.row('.active').remove().draw(false);
});
来源:https://stackoverflow.com/questions/35569962/datatable-1-10-4-delete-not-working