Remove child nodes from parent - PugiXML

问题

<Node>
  <A>
    <B id = "it_DEN"></B>
  </A>
  <A>
    <B id = "en_KEN"></B>
  </A>
  <A>
    <B id = "it_BEN"></B>
  </A>
</Node>

How can I remove child node of <A></A> that has child node <B></B> which has attribute id not starts with it using PugiXML. The result would be as below:

<Node>
  <A>
    <B id = "it_DEN"></B>
  </A>
  <A>
    <B id = "it_BEN"></B>
  </A>
</Node>

回答1:

This is slightly tricky if you want to remove nodes while iterating (to keep the code single-pass). Here's one way to do it:

bool should_remove(pugi::xml_node node)
{
    const char* id = node.child("B").attribute("id").value();
    return strncmp(id, "it_", 3) != 0;
}

for (pugi::xml_node child = doc.child("Node").first_child(); child; )
{
    pugi::xml_node next = child.next_sibling();

    if (should_remove(child))
        child.parent().remove_child(child);

    child = next;
}

Alternatively you can just use XPath and remove the results:

pugi::xpath_node_set ns = doc.select_nodes("/Node/A[B[not(starts-with(@id, 'it_'))]]");

for (auto& n: ns)
    n.node().parent().remove_child(n.node());

来源：https://stackoverflow.com/questions/37427435/remove-child-nodes-from-parent-pugixml