问题
I have a dataframe mydf
, where the Left and Right genes are separated by ':'. I need to calculate the number of occurrence of these genes in LeftGene
and RightGene
columns per file and get something like in the result. What would be the best way to do it in R?
sample LeftGene RightGene
file1
ATT:TAA
ATT:ATT ATT
file2
TTP:TTG TTP:TTP
Results
file1
LeftGene RightGene
ATT=3 ATT=1
TAA=1
file2
LeftGene RightGene
TTP=1 TTP=2
TTG=1
Attn: akrun
Here is the dput of actual data where we have file_name
, and need to get the frequency of Left.Gene.Symbols
and Right.Gene.Symbols
in each file. I would also love to see the frequency of these genes from all files (cumulative). Thank you for your help.
mydf<-structure(c("AMLM12001KP", NA, "1114002", NA, NA, NA, NA, NA,
"1121501", NA, NA, NA, "NA", "NA", "NA", "NA", "CR1L", "GIGYF2:GIGYF2:GIGYF2:ENPP3",
"NA", "NA", "NA", "NA", "NTNG1:NTNG1:ENPP3", "NA", "NA", "NA",
"NA", "NA", "CDC27:CDC27", "NA", "ENPP3", "NA", "NA", "NA", "NA",
"NA"), .Dim = c(12L, 3L), .Dimnames = list(NULL, c("files_name",
"Left.Gene.Symbols", "Right.Gene.Symbols")))
expected output:
AMLM12001KP
Left.Gene.Symbols Right.Gene.Symbols
1114002
Left.Gene.Symbols Right.Gene.Symbols
CR1L=1 CDC27=2
GIGYF2=3 ENPP3=1
ENPP3=1
1121501
Left.Gene.Symbols Right.Gene.Symbols
NTNG1=2
ENPP3=1
All files
Left.Gene.Symbol Right.Gene.Symbols
CR1L=1 CDC27=2
GIGYF2=3 ENPP3=1
NTNG1=2
ENPP3=2
回答1:
EDIT
dd2<-structure(c("AMLM12001KP", NA, "1114002", NA, NA, NA, NA, NA,"1121501", NA, NA, NA, "NA", "NA", "NA", "NA", "CR1L", "GIGYF2:GIGYF2:GIGYF2:ENPP3","NA", "NA", "NA", "NA", "NTNG1:NTNG1:ENPP3", "NA", "NA", "NA","NA", "NA", "CDC27:CDC27", "NA", "ENPP3", "NA", "NA", "NA", "NA", "NA"), .Dim = c(12L, 3L), .Dimnames = list(NULL, c("files_name", "Left.Gene.Symbols", "Right.Gene.Symbols")))
## change character NAs to <NA> and carry-forward the file column
dd2[dd2 == 'NA'] <- NA
dd2[, 1] <- na.omit(unique(dd2[, 1]))[cumsum(!is.na(dd2[, 1]))]
## split based on file name
sp <- split(data.frame(dd2, stringsAsFactors = FALSE), dd2[, 1])
## split each string by `:` and make a table
(l <- lapply(sp, function(x) {
x <- droplevels(x[, -1])
f <- function(x) na.omit(unlist(strsplit(x, ':')))
left <- f(x[, 1])
right <- f(x[, 2])
table(c(left, right), rep(names(x), c(length(left), length(right))))
}))
# $`1114002`
#
# Left.Gene.Symbols Right.Gene.Symbols
# CDC27 0 2
# CR1L 1 0
# ENPP3 1 1
# GIGYF2 3 0
#
# $`1121501`
#
# Left.Gene.Symbols
# ENPP3 1
# NTNG1 2
#
# $AMLM12001KP
# < table of extent 0 x 0 >
And since each list element is a table, work with them as tables
data.frame(l$`1114002`)
# Var1 Var2 Freq
# 1 CDC27 Left.Gene.Symbols 0
# 2 CR1L Left.Gene.Symbols 1
# 3 ENPP3 Left.Gene.Symbols 1
# 4 GIGYF2 Left.Gene.Symbols 3
# 5 CDC27 Right.Gene.Symbols 2
# 6 CR1L Right.Gene.Symbols 0
# 7 ENPP3 Right.Gene.Symbols 1
# 8 GIGYF2 Right.Gene.Symbols 0
Here's another way in a listy format
rl <- readLines(textConnection("
sample LeftGene RightGene
file1
ATT:ATT ATT
file2
TTP:TTG TTP:TTP
"))
dd <- setNames(read.table(text = rl[grep('file', rl) + 1], stringsAsFactors = FALSE),
c('LeftGene','RightGene'))
rownames(dd) <- paste0('File', 1:nrow(dd))
setNames(lapply(1:nrow(dd), function(x) {
sp <- strsplit(unlist(dd[x, ]), ':')
table(unlist(sp), rep(names(sp), lengths(sp)))
}), rownames(dd))
# $File1
#
# LeftGene RightGene
# ATT 2 1
#
# $File2
#
# LeftGene RightGene
# TTG 1 0
# TTP 1 2
or
setNames(lapply(1:nrow(dd), function(x) {
sp <- strsplit(unlist(dd[x, ]), ':')
lapply(sp, function(y) data.frame(table(y)))
}), rownames(dd))
# $File1
# $File1$LeftGene
# y Freq
# 1 ATT 2
#
# $File1$RightGene
# y Freq
# 1 ATT 1
#
#
# $File2
# $File2$LeftGene
# y Freq
# 1 TTG 1
# 2 TTP 1
#
# $File2$RightGene
# y Freq
# 1 TTP 2
回答2:
We split
the 2nd and 3rd column of 'df' with the delimiter :
, convert to 'long' format with cSplit
from splitstackshape
. The output will be a data.table
. We use melt
to reshape it again by selecting the 'id.var' as 'sample' while remove the NA
values. Grouped by 'sample', 'variable', and 'value', we get the number of rows (.N
), create new variables by paste
ing the 'value' and 'N' and a sequence variable ('ind'). Then , we dcast
from 'long' to 'wide' format.
library(splitstackshape)
library(data.table)
dM <- melt(cSplit(df, 2:3, ':', 'long'),
id.var='sample', na.rm=TRUE)[, .N,.(sample, variable, value)]
dM[, valueN:= paste(value, N, sep="=")]
dM[, ind:= 1:.N, .(sample, variable)]
dcast(dM, ind+sample~variable, value.var='valueN')
# ind sample LeftGene RightGene
#1: 1 file1 ATT=2 ATT=1
#2: 1 file2 TTP=1 TTP=2
#3: 2 file2 TTG=1 NA
data
df <- structure(list(sample = c("file1", "file2"),
LeftGene = c("ATT:ATT",
"TTP:TTG"), RightGene = c("ATT", "TTP:TTP")),
.Names = c("sample",
"LeftGene", "RightGene"), class = "data.frame",
row.names = c(NA, -2L))
来源:https://stackoverflow.com/questions/34172940/calculate-the-frequency-of-strings-separated-by-delimiter-in-different-section-o