问题
The following is my MySQL stored procedure:
DROP PROCEDURE IF EXISTS sp_authenticate;
CREATE PROCEDURE sp_authenticate(IN user_name VARCHAR(50),
IN password1 VARCHAR(50), OUT nmatch INT)
BEGIN
SELECT COUNT(*) INTO nmatch
FROM user1 u
WHERE u.name = user_name AND
u.password1 = password1;
END//
This is how I am calling it from PHP:
function authenticate($pdo, $user_name, $password){
$stmt = $pdo->prepare('CALL sp_authenticate(:user_name, :password, :nmatch)');
$stmt->bindValue(':user_name', $user_name, PDO::PARAM_STR);
$stmt->bindValue(':password', $password, PDO::PARAM_STR);
$nmatch = 888888;
$stmt->bindParam(':nmatch', $nmatch, PDO::PARAM_INT, 4);
$result = $stmt->execute();
return $nmatch;
}
$nmatch always retains it's old value and does not receive the value from the stored procedure. What could I be doing wrong here?
MySQL Server Version: 5.5.22 PHP Version: 5.3.10
回答1:
As mentioned in this blog:
Unfortunately there’s a bug with the MySQL C API that PDO uses which means that trying to fetch an output parameter when calling a procedure results in the error:
“Syntax error or access violation: 1414 OUT or INOUT argument $parameter_number for routine $procedure_name is not a variable or NEW pseudo-variable”.
You can see the bug report on bugs.mysql.com. It’s been fixed for version 5.5.3+ & 6.0.8+.
To workaround the issue, you would need to keep in & out parameters separate and call the procedure. Example #11 on the PHP PDO documentation would then read:
$stmt = $dbh->prepare("CALL sp_takes_string_returns_string(:in_string, @out_string)"); $stmt->bindParam(':in_string', 'hello'); // call the stored procedure $stmt->execute(); // fetch the output $outputArray = $this->dbh->query("select @out_string")->fetch(PDO::FETCH_ASSOC); print "procedure returned " . $outputArray['@out_string'] . "\n";
来源:https://stackoverflow.com/questions/10428480/php-bindparam-does-not-seem-to-work-with-a-param-int-out-parameter