问题
I've got the following SELECT statement, and based on what I've seen here: SQL Select Max Date with Multiple records I've got my example set up the same way. I'm on Oracle 11g. Instead of returning one record for each asset_tag, it's returning multiples. Not as many records as in the source table, but more than (I think) it should be. If I run the inner SELECT statement, it also returns the correct set of records (1 per asset_tag), which really has me stumped.
SELECT
outside.asset_tag,
outside.description,
outside.asset_type,
outside.asset_group,
outside.status_code,
outside.license_no,
outside.rentable_yn,
outside.manufacture_code,
outside.model,
outside.manufacture_vin,
outside.vehicle_yr,
outside.meter_id,
outside.mtr_uom,
outside.mtr_reading,
outside.last_read_date
FROM mp_vehicle_asset_profile outside
RIGHT OUTER JOIN
(
SELECT asset_tag, max(last_read_date) as last_read_date
FROM mp_vehicle_asset_profile
group by asset_tag
) inside
ON outside.last_read_date=inside.last_read_date
Any suggestions?
回答1:
I think you need to add...
AND outside.asset_tag=inside.asset_tag
...to the criteria in your ON
list.
Also a RIGHT OUTER JOIN
is not needed. An INNER JOIN
will give the same results (and may be more efficicient), since there will be cannot be be combinations of asset_tag
and last_read_date
in the subquery that do not exist in mp_vehicle_asset_profile
.
Even then, the query may return more than one row per asset tag if there are "ties" -- that is, multiple rows with the same last_read_date
. In contrast, @Lamak's analytic-based answer will arbitrarily pick exactly one row this situation.
Your comment suggests that you want to break ties by picking the row with highest mtr_reading
for the last_read_date
.
You could modify @Lamak's analyic-based answer to do this by changing the ORDER BY
in the OVER
clause to:
ORDER BY last_read_date DESC, mtr_reading DESC
If there are still ties (that is, multiple rows with the same asset_tag
, last_read_date
, and mtr_reading
), the query will again abritrarily pick exactly one row.
You could modify my aggregate-based answer to break ties using highest mtr_reading
as follows:
SELECT
outside.asset_tag,
outside.description,
outside.asset_type,
outside.asset_group,
outside.status_code,
outside.license_no,
outside.rentable_yn,
outside.manufacture_code,
outside.model,
outside.manufacture_vin,
outside.vehicle_yr,
outside.meter_id,
outside.mtr_uom,
outside.mtr_reading,
outside.last_read_date
FROM
mp_vehicle_asset_profile outside
INNER JOIN
(
SELECT
asset_tag,
MAX(last_read_date) AS last_read_date,
MAX(mtr_reading) KEEP (DENSE_RANK FIRST ORDER BY last_read_date DESC) AS mtr_reading
FROM
mp_vehicle_asset_profile
GROUP BY
asset_tag
) inside
ON
outside.asset_tag = inside.asset_tag
AND
outside.last_read_date = inside.last_read_date
AND
outside.mtr_reading = inside.mtr_reading
If there are still ties (that is, multiple rows with the same asset_tag
, last_read_date
, and mtr_reading
), the query may again return more than one row.
One other way that the analytic- and aggregate-based answers differ is in their treatment of nulls. If any of asset_tag
, last_read_date
, or mtr_reading
are null, the analytic-based answer will return related rows, but the aggregate-based one will not (because the equality conditions in the join do not evaluate to TRUE
when a null is involved.
回答2:
Try with analytical functions:
SELECT outside.asset_tag,
outside.description,
outside.asset_type,
outside.asset_group,
outside.status_code,
outside.license_no,
outside.rentable_yn,
outside.manufacture_code,
outside.model,
outside.manufacture_vin,
outside.vehicle_yr,
outside.meter_id,
outside.mtr_uom,
outside.mtr_reading,
outside.last_read_date
FROM ( SELECT *, ROW_NUMBER() OVER(PARTITION BY asset_tag ORDER BY last_read_date DESC) Corr
FROM mp_vehicle_asset_profile) outside
WHERE Corr = 1
来源:https://stackoverflow.com/questions/10761665/oracle-select-max-date-on-multiple-records