LayerDrawable programmatically

主宰稳场 提交于 2019-11-27 04:50:46

问题


Since my application's color theme is dynamic i can only create background drawables using colors and shapedrawables, i want to build a edittext background drawable with colors and shapes as shown below. But i want to do this programatically

How to build this same drawable programatically?

<item>
    <shape>
        <solid android:color="@android:color/yellow" />
    </shape>
</item>

<!-- main color -->
<item
    android:bottom="1dp"
    android:left="1dp"
    android:right="1dp">
    <shape>
        <solid android:color="@android:color/white" />
    </shape>
</item>

<!-- draw another block to cut-off the left and right bars -->
<item android:bottom="10dp">
    <shape>
        <solid android:color="@android:color/white" />
    </shape>
</item>

this is what i tried....

    GradientDrawable border = new GradientDrawable();
    border.setShape(GradientDrawable.RECTANGLE);
    border.setColor(Color.WHITE);

    GradientDrawable background = new GradientDrawable();
    background.setShape(GradientDrawable.RECTANGLE);
    background.setColor(Color.YELLOW);


    GradientDrawable clip = new GradientDrawable();
    clip.setShape(GradientDrawable.RECTANGLE);
    border.setColor(Color.WHITE);

    Drawable[] layers = {background, border, clip};
    LayerDrawable layerDrawable = new LayerDrawable(layers);

    layerDrawable.setLayerInset(0, 0, 0, 0, 0);
    layerDrawable.setLayerInset(1, 1, 0, 1, 1);
    layerDrawable.setLayerInset(2, 0, 0, 0, 10);

but the result is different....please help....!


回答1:


I finally got it working. Instead of using GradientDrawable I used ShapeDrawable.

By setting this LayerDrawable as an EditText background you can regenerate default EditText styles with custom colors.

ShapeDrawable border = new ShapeDrawable();
border.getPaint().setColor(Color.WHITE);

ShapeDrawable background = new ShapeDrawable();
background.getPaint().setColor(Color.BLACK);


ShapeDrawable clip = new ShapeDrawable();
clip.getPaint().setColor(Color.WHITE);

Drawable[] layers = {background, border, clip};
LayerDrawable layerDrawable = new LayerDrawable(layers);

layerDrawable.setLayerInset(0, 0, 0, 0, 0);
layerDrawable.setLayerInset(1, 1, 0, 1, 1);
layerDrawable.setLayerInset(2, 0, 0, 0, 10);



回答2:


This also works with Gradient Drawables:

GradientDrawable border = new GradientDrawable();
border.setColor(Color.White);

GradientDrawable background = new GradientDrawable();
background.setColor(Color.Black);

GradientDrawable clip = new GradientDrawable();
clip.setColor(Color.White);

GradientDrawable[] layers = {background, border, clip};
LayerDrawable layerDrawable = new LayerDrawable(layers);

layerDrawable.setLayerInset(0, 0, 0, 0, 0);
layerDrawable.setLayerInset(1, 1, 0, 1, 1);
layerDrawable.setLayerInset(2, 0, 0, 0, 10);


来源:https://stackoverflow.com/questions/20120725/layerdrawable-programmatically

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!