Haskell Yesod - extracting a object inside a json before converting it to a model

问题

Suppose I have a JSON like this:

{
  data: {...}
}

and {...} represents a model of mine. How could get my model in this case in the Handler? For instance, the following will not work obviously:

putMyEntityR :: Handler ()
putMyEntityR = do
  (Entity id _) <- (...) -- getting the Key
  e <- requireJsonBody :: Handler MyEntity
  runDB $ replace id e
  sendResponseStatus status204 ("UPDATED" :: Text)

How can I read the JSON, take the data object, and only then decode it?

回答1:

There was some more discussion of this question on a Github Issue, which I'm adding as an answer here because it's more fleshed out. Here's what we arrive at for the Handler function using the helper functions defined below:

postDataCommentR :: Handler Value
postDataCommentR = do
  value <- requireJsonBody' -- Parse request body into Value
  commentJson <- requireJsonKey "data" value -- Lookup a key from the Value
  comment <- (requireJsonParse commentJson :: Handler Comment) -- Parse the Value into a comment record

  insertedComment <- runDB $ insertEntity comment
  returnJson insertedComment

These functions take the request body and parse it into an aeson Value:

import qualified Data.Aeson as J
import qualified Data.Aeson.Parser as JP
import Data.Conduit.Attoparsec (sinkParser)

-- These two functions were written by @FtheBuilder
parseJsonBody' :: (MonadHandler m) => m (J.Result Value)
parseJsonBody' = do
    eValue <- rawRequestBody $$ runCatchC (sinkParser JP.value')
    return $ case eValue of
        Left e -> J.Error $ show e
        Right value -> J.Success value

-- | Same as 'parseJsonBody', but return an invalid args response on a parse
-- error.
requireJsonBody' :: (MonadHandler m) => m Value
requireJsonBody' = do
    ra <- parseJsonBody'
    case ra of
        J.Error s -> invalidArgs [pack s]
        J.Success a -> return a

These helper functions are used to parse that Value into a record:

requireJsonParse :: (MonadHandler m, FromJSON a) => Value -> m a
requireJsonParse v = case J.fromJSON v of
  J.Error s -> invalidArgs [pack s]
  J.Success a -> return a

requireJsonKey :: (MonadHandler m) => Text -> Value -> m Value
requireJsonKey key jObject@(Object hashMap) = case lookup key hashMap of
                                    Nothing -> invalidArgs ["Couldn't find a value when looking up the key " <> key <> " in the object: " <> (pack (show jObject))]
                                    Just v -> return v
requireJsonKey key invalid = invalidArgs ["When looking up the key " <> key <> ", expected an object but got a " ++ (pack (show invalid))]

Commentary

aeson-lens

I didn't use aeson-lens, but the code is pretty similar with or without it, since we're just going one key deep. aeson-lens would make things nicer if we were traversing deeper into the JSON.

Comparison to wrapper definition

Once you get the helper functions defined, you still have a couple lines to parse a Value, then lookup the data key, then create your record. You can do things to make this shorter, but ultimately the wrapper that @Carsten recommended would be of similar length with less complexity, imo.

回答2:

This was too large to fit in my comment above (using lens-aeson)

λ: import Control.Lens
λ: import Data.Aeson.Lens
λ: let e = "{ \"data\": [1,2,3] }"
λ: e ^? key "data"
Just (Array [Number 1.0,Number 2.0,Number 3.0])

and as Carsten mentioned, you'll still need to provide a FromJSON instance of your model

来源：https://stackoverflow.com/questions/35816074/haskell-yesod-extracting-a-object-inside-a-json-before-converting-it-to-a-mode

标签

haskell

yesod

aeson