问题
Is there a way of modifing the algorithm in
Finding all cycles in undirected graphs
to consider edges as directed and only cycles of length <= k ?
回答1:
I reply by myself
static void Main(string[] args)
{
int k = 4;
for (int i = 0; i < graph.GetLength(0); i++)
for (int j = 0; j < graph.GetLength(1); j++)
{
findNewCycles(new int[] { graph[i, j] },k);
}
foreach (int[] cy in cycles)
{
string s = "" + cy[0];
for (int i = 1; i < cy.Length; i++)
s += "," + cy[i];
Console.WriteLine(s);
}
}
static void findNewCycles(int[] path, int k)
{
int n = path[0];
int x;
int[] sub = new int[path.Length + 1];
if (path.Length < k + 1)
{
for (int i = 0; i < graph.GetLength(0); i++)
for (int y = 0; y <= 1; y = y + 2)
if (graph[i, y] == n)
// edge referes to our current node
{
x = graph[i, (y + 1) % 2];
if (!visited(x, path))
// neighbor node not on path yet
{
sub[0] = x;
Array.Copy(path, 0, sub, 1, path.Length);
// explore extended path
findNewCycles(sub,k);
}
else if ((path.Length > 2) && (x == path[path.Length - 1]))
// cycle found
{
int[] p = normalize(path);
int[] inv = invert(p);
if (isNew(p) && isNew(inv))
cycles.Add(p);
}
}
}
}
static bool equals(int[] a, int[] b)
{
bool ret = (a[0] == b[0]) && (a.Length == b.Length);
for (int i = 1; ret && (i < a.Length); i++)
if (a[i] != b[i])
{
ret = false;
}
return ret;
}
static int[] invert(int[] path)
{
int[] p = new int[path.Length];
for (int i = 0; i < path.Length; i++)
p[i] = path[path.Length - 1 - i];
return normalize(p);
}
// rotate cycle path such that it begins with the smallest node
static int[] normalize(int[] path)
{
int[] p = new int[path.Length];
int x = smallest(path);
int n;
Array.Copy(path, 0, p, 0, path.Length);
while (p[0] != x)
{
n = p[0];
Array.Copy(p, 1, p, 0, p.Length - 1);
p[p.Length - 1] = n;
}
return p;
}
static bool isNew(int[] path)
{
bool ret = true;
foreach (int[] p in cycles)
if (equals(p, path))
{
ret = false;
break;
}
return ret;
}
static int smallest(int[] path)
{
int min = path[0];
foreach (int p in path)
if (p < min)
min = p;
return min;
}
static bool visited(int n, int[] path)
{
bool ret = false;
foreach (int p in path)
if (p == n)
{
ret = true;
break;
}
return ret;
}
}
来源:https://stackoverflow.com/questions/14877905/finding-all-cycles-in-directed-graphs-of-length-k