问题
Background
I have the following toy df
that contains lists in the columns Before
and After
as seen below
import pandas as pd
before = [list(['in', 'the', 'bright', 'blue', 'box']),
list(['because','they','go','really','fast']),
list(['to','ride','and','have','fun'])]
after = [list(['there', 'are', 'many', 'different']),
list(['i','like','a','lot','of', 'sports']),
list(['the','middle','east','has','many'])]
df= pd.DataFrame({'Before' : before,
'After' : after,
'P_ID': [1,2,3],
'Word' : ['crayons', 'cars', 'camels'],
'N_ID' : ['A1', 'A2', 'A3']
})
Output
After Before N_ID P_ID Word
0 [in, the, bright, blue, box] [there, are, many, different] A1 1 crayons
1 [because, they, go, really, fast] [i, like, a, lot, of, sports ] A2 2 cars
2 [to, ride, and, have, fun] [the, middle, east, has, many] A3 3 camels
Problem
Using the following block of code:
df.loc[:, ['After', 'Before']] = df[['After', 'Before']].apply(lambda x: x.str[0].str.replace(',', ''))
taken from Removing commas and unlisting a dataframe produce the following output:
Close-to-what-I-want-but-not-quite- Output
After Before N_ID P_ID Word
0 in there A1 1 crayons
1 because i A2 2 cars
2 to the A3 3 camels
This output is close but not quite what I am looking for because After
and Before
columns have only one word outputs (e.g. there
) when my desired output looks as such:
Desired Output
After Before N_ID P_ID Word
0 in the bright blue box there are many different A1 1 crayons
1 because they go really fast i like a lot of sports A2 2 cars
2 to ride and have fun the middle east has many A3 3 camels
Question
How do I get my Desired Output?
回答1:
agg
+ join
. The commas aren't present in your lists, they are just part of the __repr__
of the list.
str_cols = ['Before', 'After']
d = {k: ' '.join for k in str_cols}
df.agg(d).join(df.drop(str_cols, 1))
Before After P_ID Word N_ID
0 in the bright blue box there are many different 1 crayons A1
1 because they go really fast i like a lot of sports 2 cars A2
2 to ride and have fun the middle east has many 3 camels A3
If you'd prefer in place (faster):
df[str_cols] = df.agg(d)
回答2:
applymap
In line
New copy of a dataframe with desired results
df.assign(**df[['After', 'Before']].applymap(' '.join))
Before After P_ID Word N_ID
0 in the bright blue box there are many different 1 crayons A1
1 because they go really fast i like a lot of sports 2 cars A2
2 to ride and have fun the middle east has many 3 camels A3
In place
Mutate existing df
df.update(df[['After', 'Before']].applymap(' '.join))
df
Before After P_ID Word N_ID
0 in the bright blue box there are many different 1 crayons A1
1 because they go really fast i like a lot of sports 2 cars A2
2 to ride and have fun the middle east has many 3 camels A3
stack
and str.join
We can use this result in a similar "In line" and "In place" way as shown above.
df[['After', 'Before']].stack().str.join(' ').unstack()
After Before
0 there are many different in the bright blue box
1 i like a lot of sports because they go really fast
2 the middle east has many to ride and have fun
回答3:
We can specify the lists we want to convert to string and then use .apply
in a for loop:
lst_cols = ['Before', 'After']
for col in lst_cols:
df[col] = df[col].apply(' '.join)
Before After P_ID Word N_ID
0 in the bright blue box there are many different 1 crayons A1
1 because they go really fast i like a lot of sports 2 cars A2
2 to ride and have fun the middle east has many 3 camels A3
来源:https://stackoverflow.com/questions/56918887/turn-lists-of-lists-into-strings-pandas-dataframe