问题
Right now I have flask-script command that takes a path as an argument, then reads from the path:
@manager.option('-f', '--file', dest='file_path')
def my_command(file_path):
open(file_path)
...
I'd want it to be able to read from standard in as well. (I frequently need to pass it text on the clipboard, and it's annoying to have to create a file each time.)
How can I accomplish this?
I've tried using fileinput.input()
, via this https://stackoverflow.com/a/1454400/1164573, invoked with the following:
cat << EOF | ./manage.py my_command
abc
def
ghi
EOF
But fileinput.input()
is empty. Is this because flask-script is wrapping my function and not exposing standard in to it directly? How can I get around this?
回答1:
You could do it almost like your example, but using process substitution instead of a pipe:
./manage.py my_command <(cat <<EOF
abc
def
ghi
jkl
EOF
)
works for my simple test. . . assuming you're using bash for your shell at least. I only use bash, so don't know if this syntax works for other shells.
Alternately, you could test the value of the filename for a special value, typically -
and use sys.stdin
if that's the name of the file to read.
if(sys.argv[1] == '-'):
f = sys.stdin
else:
f = file(sys.argv[1])
for line in f:
print line
and so forth
来源:https://stackoverflow.com/questions/32084321/reading-from-standard-input-using-flask-script-python