问题
I am building an object with a simple loop:
WebTarget target = getClient().target(u);
for (Entry<String, String> queryParam : queryParams.entrySet()) {
target = target.queryParam(queryParam.getKey(), queryParam.getValue());
}
I want to do the same thing using the Java8 Stream API but I cannot figure out how to do it. What makes me struggle is that target is reassigned every time, so a simple .forEach() will not work. I guess I need to use a .collect() or reduce() since I am looking for a single return value but I am lost at the moment!
回答1:
There's unfortunately no foldLeft
method in the stream API. The reason for this is explained by Stuart Marks in this answer:
[...] Finally, Java doesn't provide
foldLeft
andfoldRight
operations because they imply a particular ordering of operations that is inherently sequential. This clashes with the design principle stated above of providing APIs that support sequential and parallel operation equally.
Ultimately what you're trying to do here is something procedural / sequential so I don't think the stream API is a good fit for this use case. I think the for-each loop that you have posted yourself is as good as it gets.
Update:
As @TagirValeev points out below you can in fact solve it with the stream API (using forEachOrdered. Your code would then look something like
WebTarget[] arr = { getClient().target(u) };
queryParams.entrySet()
.stream()
.forEachOrdered(e -> arr[0] = arr[0].queryParam(e.getKey(),
e.getValue()));
WebTarget target = arr[0];
I stand by my original answer though, and claim that your good old for-loop is a better approach in this case.
回答2:
It's not very difficult to implement a correct foldLeft
for Java 8 streams:
@SuppressWarnings("unchecked")
public static <T, U> U foldLeft(Stream<T> stream,
U identity, BiFunction<U, ? super T, U> accumulator) {
Object[] result = new Object[] { identity };
stream.forEachOrdered(t -> result[0] = accumulator.apply((U) result[0], t));
return (U) result[0];
}
Or in type-safe manner:
public static <T, U> U foldLeft(Stream<T> stream,
U identity, BiFunction<U, ? super T, U> accumulator) {
class Box {
U value;
Box(U value) { this.value = value; }
}
Box result = new Box(identity);
stream.forEachOrdered(t -> result.value = accumulator.apply(result.value, t));
return result.value;
}
This works correctly for sequential and parallel streams. You can even have a speed gain using parallel streams if your stream has some CPU-consuming stateless intermediate operations like map
: in this case the next element can be processed by map
in the parallel with the current element processed by foldLeft
. I don't agree that such operation is not suitable for Stream API, because it can be correctly expressed via already existing forEachOrdered
.
I have this operation in my StreamEx library, so you can use it like this:
WebTarget target = EntryStream.of(queryParams).foldLeft(getClient().target(u),
(t, entry) -> t.queryParam(entry.getKey(), entry.getValue()))
来源:https://stackoverflow.com/questions/30736587/builder-pattern-with-a-java-8-stream