问题
I was using GetDIBits
to get bitmap data from a screen compatible device context into a DIB of a certain format. I was under the impression that the DC was necessary only for synthesizing a color table when the source bitmap is 8 bits-per-pixel or less. Since my source bitmap was a full 32-bit color image and this was a one-off program and I didn't have the screen DC handy, I set the HDC parameter to NULL. This didn't work. Once I grabbed the screen DC and passed it in, it did start working.
That left me wondering why GetDIBits
requires the device context. What is it used for?
回答1:
In:
int SetDIBits(
__in HDC hdc,
__in HBITMAP hbmp,
__in UINT uStartScan,
__in UINT cScanLines,
__in const VOID *lpvBits,
__in const BITMAPINFO *lpbmi,
__in UINT fuColorUse
);
The second argument hbmp
is the device dependent bitmap that will be altered using the color information from the device independent bitmap. The hdc
is a handle to the device context on which this (device dependent) bitmap depends. When the call is made, Windows uses information from this device context to decide how to perform the transformation.
来源:https://stackoverflow.com/questions/3962237/what-is-the-hdc-for-in-getdibits