问题
I have code like this, the value of jArrAnswer
is
[{"answer":"Yes"},{"answer":"No"},{"answer":"maybe"},{"answer":"yrg"}]
the result from jArrAnswer.length()
is 4
but why I got error
org.json.JSONException: Index 1 out of range [0..1).
try {
JSONArray jArrAnswerid = new JSONArray(answerid);
JSONArray jArrAnswer = new JSONArray(answer);
for (int i = 0; i < jArrAnswer.length(); i++) {
JSONObject jObjAnswerid = jArrAnswerid.getJSONObject(i);
JSONObject jObjAnswer = jArrAnswer.getJSONObject(i);
String ansid = jObjAnswerid.getString("answerid");
String ans= jObjAnswer.getString("answer");
GroupModel item2 = new GroupModel(String.valueOf(i + 1), ans, ansid);
}
} catch (Exception e) {
Log.w("asdf", e.toString());
}
回答1:
You are iterating the for loop
over jArrAnswer
while your fetching the index i
over jArrAnswerid
.
Check and make sure that the jArrAnswerid.size()
is equal to the jArrAnswer.size()
.
Print the jArrAnswerid.size()
and check.
回答2:
Try this
try {
JSONArray jArrAnswer = new JSONArray(answer);
for (int i = 0; i < jArrAnswer.length(); i++) {
JSONObject jObjAnswer = jArrAnswer.getJSONObject(i);
String ansid = jObjAnswer.getString("answerid");
String ans= jObjAnswer.getString("answer");
}
} catch (Exception e) {
Log.w("asdf", e.toString());
}
provided "answer" is your json array response
回答3:
Try
String json = "[{\"answer\":\"Yes\",\"answerid\":\"1\"},{\"answer\":\"No\",\"answerid\":\"2\"},{\"answer\":\"maybe\",\"answerid\":\"3\"},{\"answer\":\"yrg\",\"answerid\":\"4\"}]";
try {
JSONArray jsonArray = new JSONArray(json);
if(jsonArray != null) {
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject jsonObject = jsonArray.getJSONObject(i);
String answerId = jsonObject.getString("answerid");
String answer = jsonObject.getString("answer");
//Use answerId and answer
}
}
} catch(JSONException e) {
e.printStackTrace();
}
来源:https://stackoverflow.com/questions/46418094/android-jsonexception-index-1-out-of-range-0-1-parse-2-json-arrays-inside-1