问题
How to parse this json? I want get data from title, field_place and brothers fields.
{
"events": [
{
"event": {
"title": "BITUMIX Martyna Jastrz\u0119bska",
"field_place": "Nowe Miejsce Al Jerozolimskie 51 lok.2",
"field_zdjecie": "http:\/\/wybierzkulture.waw.pl\/sites\/default\/files\/styles\/post\/public\/martyna_jastrzebska_bitumix_2.jpg?itok=nd2O5U5z"
}
},
{
"event": {
"title": "Wiecz\u00f3r Komedii Improwizowanej - D\u017cem Impro!",
"field_place": "",
"field_zdjecie": "http:\/\/wybierzkulture.waw.pl\/sites\/default\/files\/styles\/post\/public\/dzem_17_maja.jpg?itok=bfgDYxKq"
}
},
...
I tried:
JSONObject itemm = jArray.getJSONObject(i);
JSONObject oneObject = itemm.getJSONObject("event");
String title = oneObject.getString("title");
String field_place = oneObject.getString("field_place");
... but it doesn't work.
回答1:
In a JSON string , there are two symbols that guide you through parsing :
{ - indicates a JSONObject
[ - indicates a JSONArray
When parsing a json string, you should go through this items iteratively. To understand how many JsonObjects and JsonArrays you have in your string , and from which you should start parsing, use a json-visualizer tool like this website. :
Example : As you see, the root object is a JSONObject which consists of an JSONArray with three jsonOnjects. To parse such a structure you can use :
JSONObject jsonobj = new JSONObject(jsonstring);
String result = jsonObject.getString("success");
String error_number = jsonObject.getString("error_number");
String error_message = jsonObject.getString("error_message");
JSON Array jsonarray = jsonobj.getJSONArray();
String[] names = new String[jsonArray.length()];
String[] formattedNames = new String[jsonArray.length()];
for(int i=0;i<jsonArray.length();i++)
{
JSONObject jsonObject = jsonArray.getJSONObject(i);
names [i] = jsonObject.getString("name");
formattedNames [i] = jsonObject.getString("formattedName");
}
回答2:
try this
JSONArray element = jsonobj.getJSONArray("events");
for(int i=0;i < element.length();i++){
JSONObject e = element.getJSONObject(i);
Log.d("TESTTT22",e.getJSONObject("event").getString("title"));
}
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
来源:https://stackoverflow.com/questions/23667072/json-parse-android-object-in-object