问题
As an exercise for school I wrote a method in Java that searches for a character in a file. Here is the code:
public static void countLetter(char needle, String hayStack) throws IOException {
File f = new File(hayStack);
try (Scanner in = new Scanner(f)) {
String str = null;
while (in.hasNext()){
str += in.next();
}
char[] charArr = str.toCharArray();
int counter = 0;
for (char c: charArr) {
if (c == needle){
counter++;
}
}
System.out.println(counter);
}
}
This does what I need it to but I have a question. Is the file object ever opened? And if it is, does it ever closed? I used try-with-resources on the Scanner object so I'm pretty sure I don't have to explicitly close that, but what about the file object?
回答1:
File object is just an abstract representation of a pathname, it has nothing to do with opening a file. So it can not be closed.
回答2:
The File object can not be opened (and therefore can not be closed) as it is a representation of a file path and not a representation of a file.
The Scanner class opens your file in order to read it. Your program doesn't call in.close() so when your method returns the Scanner will not be garbage collected as it still has a reference to an open file. You may also be locking the file depending on how the file was opened by the Scanner.
In order for a class to qualify for automatically closing resources in a try-resource block the class must implement java.lang.AutoCloseable (or java.io.Closeable). Scanner does not implement these interfaces and so it won't have its close() method called when you exit the try-resource block.
Alter the code to:
public static void countLetter(char needle, String hayStack) throws IOException {
File f = new File(hayStack);
try (Scanner in = new Scanner(f)) {
String str = null;
while (in.hasNext()){
str += in.next();
}
char[] charArr = str.toCharArray();
int counter = 0;
for (char c: charArr) {
if (c == needle){
counter++;
}
}
System.out.println(counter);
in.close();
}
}
回答3:
As the variable is local to your function so it will go out of scope once the function exists, and eventually garbage collection. Answer to your question is NO, in your case file object is not ever opened.
来源：https://stackoverflow.com/questions/16390819/is-this-file-object-left-open