How to stop executing next function with async-await?

问题

I'm using this library to chain asynchronous functions in my nodejs app: https://github.com/yortus/asyncawait

var chain = async(function(){

    var foo = await(bar());
    var foo2 = await(bar2());
    var foo3 = await(bar2());

}

So bar3 waits for bar2 to finish and bar2 waits for bar() to finish. That's fine. But what will I do in order to stop the async block from further execution? I mean something like this:

var chain = async(function(){

    var foo = await(bar());
    if(!foo){return false;} // if bar returned false, quit the async block
    var foo2 = await(bar2());
    var foo3 = await(bar2());

}

what's the best approach to handle this?

at the moment I throw an exception within bar and handle the exception in way:

chain().catch(function (err) { //handler, ie log message)

It's working, but it doesn't look right

回答1:

I mean something like this …

asyncawait supports exactly this syntax. Just return from the function:

var chain = async(function(){
    var foo = await(bar());
    if (!foo) return;
    var foo2 = await(bar2());
    var foo3 = await(bar2());
});

来源：https://stackoverflow.com/questions/28835780/how-to-stop-executing-next-function-with-async-await