问题
Working on converting my mysql php code to sqlsrv, but having issue finding the same functions.
This is the code:
$result=sqlsrv_query($conn,$sql) or die("Couldn't execute query:<br>" . sqlsrv_error(). "<br>" . sqlsrv_errno());
$file_ending = "xls";
$reals=array();
//header info for browser
header("Content-Type: application/xls");
header("Content-Disposition: attachment; filename=$filename.xls");
header("Pragma: no-cache");
header("Expires: 0");
/*******Start of Formatting for Excel*******/
//define separator (defines columns in excel & tabs in word)
$sep = "\t"; //tabbed character
//start of printing column names as names of MySQL fields
/*for ($i = 0; $i < sqlsrv_num_fields($result); $i++) {
$type = sqlsrv_field_metadata($result,$i);
echo sqlsrv_field_metadata($result,$i) . "\t";
if ($type == "real")
{
$reals[] = $i;
}
}
*/
$i=0;
foreach( sqlsrv_field_metadata( $result ) as $fieldMetadata ) {
echo $fieldMetadata["Name"]+"\t";
if($fieldMetadata["Type"]=="real")//$fieldMetadata["Type"]=== SQL_REAL
{
$reals[] = $i;
}
$i++;
}
print("\n");
//end of printing column names
//start while loop to get data
while($row = sqlsrv_num_rows($result))
{
$schema_insert = "";
for($j=0; $j<sqlsrv_num_fields($result);$j++)
{
if(!isset($row[$j]))
$schema_insert .= "NULL".$sep;
elseif ($row[$j] != ""){
if (in_array($j, $reals)){
$schema_insert .= str_replace(".",",","$row[$j]").$sep;
} else {
$schema_insert .= "$row[$j]".$sep;
}
}
else
$schema_insert .= "".$sep;
}
$schema_insert = str_replace($sep."$", "", $schema_insert);
$schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert);
$schema_insert .= "\t";
print(trim($schema_insert));
print "\n";
}
I am unsure what the field_type and field_name is equlent in sqlsrv, but this didn't work:
for ($i = 0; $i < sqlsrv_num_fields($result); $i++) {
$type = sqlsrv_get_field($result,$i);
echo sqlsrv_get_field($result,$i) . "\t";
if ($type == "real")
{
$reals[] = $i;
}
}
回答1:
I am an ASP.Net developer with very little knowledge about PHP. May be something like below will be useful to you. Just check once.
$stmt = sqlsrv_prepare( $conn, $sql );
$result=sqlsrv_query($conn, $sql);
$i=0;
foreach( sqlsrv_field_metadata( $stmt ) as $fieldMetadata ) {
echo $fieldMetadata["Name"]+"\t";
if($fieldMetadata["Type"]=="real")//$fieldMetadata["Type"]=== SQL_REAL
{
$reals[] = $i
}
$i++;
}
I have not run it before posting here, please let me know in case it's not working.
回答2:
sqlsrv_field_metadata()
can provide the information you need, see Microsofts documentation
The type should be 7 (SQL_REAL) for real or 6 (SQL_FLOAT) for float.
来源:https://stackoverflow.com/questions/23214652/mysql-to-sqlsrv