问题
This program is supposed to print the first x prime numbers, but I noticed that it was printing some non-prime numbers, such as 27 or 35. I've been looking at it for hours and nothing seems to pop up. So please, if you know what's wrong, tell me.
#include <stdio.h>
int main(){
int i=0, cont=2, prim=2, quant;
printf("Insert number of prime numbers you wish: ");
scanf("%d", &quant);
printf("The first %d prime numbers are:\n", quant);
while(i<quant){
if(prim%cont!=0 && (cont>1 && cont<prim)){
cont++;
}
else if(prim%cont==0 && (cont>1 && cont<prim)){
prim++;
}
else if(prim%cont==0 && cont==prim){
printf("%d\n", prim);
prim++;
cont=2;
i++;
}
}
return 0;
}
回答1:
Code:
int count = 0, quant = 5, i, j;
int flag = 0;
for(prim = 2 ; count <= quant ; prim ++) {
flag = 0;
for(j = 2; j < prim/2; j++) {
if(prim % j == 0) {
flag = 1;
break;
}
}
if(flag == 0) {
printf("%d\n", prim);
count++;
}
}
Update your code as:
while(i<quant){
if(cont<prim) {
if(prim%cont!=0) {
cont++;
} else {
prim++;
cont = 2; // restart cont
}
}
else if(prim%cont==0 && cont==prim){
printf("%d\n", prim);
prim++;
cont=2;
i++;
}
}
回答2:
Try this
#include<stdio.h>
int prime(int n)
{
int i, j, len=1, brk=0;
int list[200]={2};
for(i=2; i<=n; i++)
{
for(j=0; j<len; j++)
{
if(i%list[j]==0){
brk=1;
break;
}
else
{
brk=0;
}
}
if(brk==0)
{
list[len]=i;
len++;
}
}
for(i=0; i<len; i++)
printf("%d ",list[i]);
}
main()
{
int i, n;
scanf("%d",&n);
prime(n);
}
回答3:
Simple way is to find is: if a number is not divisible by 2,3 & 5, its a prime number.
#include <stdio.h>
int main()
{
int num = 35;
int i = 5;
printf("1 2 3 5");
while (i <= num)
{
if ((i % 2) && (i % 3) && (i % 5))
{
printf(" %d",i);
}
i++;
}
printf("\n");
return 0;
}
来源:https://stackoverflow.com/questions/26667217/prime-number-program-in-c