Bash - change path to the folder with the highest version number

问题

I have the below folder structure

MyPackage
  └── versions
      └── MyPackage-1.0
          └── src
          MyPackage-1.0.1
          └── src
          MyPackage-2.0
          └── src

I am writing a bash script to build the latest version of the package and retrieve the build artifact. Part of that step is to change to the directory of the latest package:

cd MyPackage/versions/MyPackage-2.0/src

How can I write my bash script such that it will always choose the highest version subfolder (so in this case MyPackage-2.0 but in the future it could become MyPackage-2.0.1 or MyPackage-2.1)?

回答1:

With the help of GNU sort you can do the following:

cd "$(printf "%s"$'\n' MyPackage/versions/* | sort -Vr | head -n1)"

Broken down:

$ printf "%s"$'\n' MyPackage/versions/*
MyPackage/versions/MyPackage-1.0
MyPackage/versions/MyPackage-1.0.1
MyPackage/versions/MyPackage-2.0
$ printf "%s"$'\n' MyPackage/versions/* | sort -Vr
MyPackage/versions/MyPackage-2.0
MyPackage/versions/MyPackage-1.0.1
MyPackage/versions/MyPackage-1.0
$ printf "%s"$'\n' MyPackage/versions/* | sort -Vr | head -n1
MyPackage/versions/MyPackage-2.0

来源：https://stackoverflow.com/questions/57805676/bash-change-path-to-the-folder-with-the-highest-version-number

标签

bash