问题
I have the following code that needs to be duplicated:
<form method="post">
<div id="field-row-container">
<div id="field-row-1" class="field-row">
<div class="field-element">
<label for="Name[1]">Name</label>
<input type="text" id="Name[1]" name="Name[]" />
</div>
<div class="field-element">
<label for="Email[1]">Email</label>
<input type="text" id="Email[1]" name="Email[]" />
</div>
<hr/>
</div>
</div>
<div class="form-element">
<input type="button" class="confirm add-field-row" value="Add" />
<input type="button" class="danger delete-field-row" value="Delete" />
<input type="submit" />
</div>
The duplicated / dynamically added elements will have the same names of Name[]
and Email[]
but their ID's will be incremented.
The JavaScript is below, based from Josiah Ruddell's form duplication script.
var template = $('#field-row-container #field-row-1').clone();
window.addForm = function () {
var parent = $(this).closest('.dynamic-rows').attr('id');
var fieldRowCount = countRows(parent) + 1;
var newFieldRow = template.clone().find(':input').each(function () {
var newId = this.id.substring(0, this.id.length - 3) + "[" + fieldRowCount + "]";
$(this).prev().attr('for', newId); // update label for
this.id = newId; // update id and name (assume the same)
$(this).closest('.field-row').addClass('new-row');
}).end()
.attr('id', 'field-row-' + fieldRowCount)
.appendTo('#field-row-container');
}
$('.add-field-row').click(addForm);
Whenever I submit the form to CodeIgniter and if there is a validation error, once the controller reloads the multi-part form, the dynamically added elements disappear as well as the values in the initial fields.
How do I go around this problem? I'm at a loss on how to solve this...
Other notes that might help:
- This is a component multi-part form with only one form controller
- I have multiple instances of this - Addresses, Education Degrees and such
- I use CodeIgniter's
form_validation
library to check server-side each array of posts
回答1:
When the page with the form on reloads after the controllers redirects back to it after failing validation, it will only reload the original page, with no DOM manipulations applied.
I would perform the POST request which submits the form via ajax, so you can handle the response without leaving the page. Something like this:
$.post('/locationOfController.php', $('#yourForm').serialize(), function(response){
if(response.valid){
window.location.href = '/somewhereAfterFormPosted.php';
} else {
$('#yourForm').append("<p>"+response.error+"</p>");
}
}, 'json');
and change the controller to return a JSON object based on whether validation passed or not. To match up with my example above, you would return something like below when an error occurs:
{valid: false, error: 'Please fill out the whole form'}
Try something like that as a basic example. You could do much more, such as returning several errors if multiple fields are invalid.
来源:https://stackoverflow.com/questions/14797551/dynamically-duplicated-forms-disappear-on-codeigniter-reload