问题
I'm working on Python 2.7. I have to define some Areas of Interest (AoI) on a picture. Basically, I'm trying to do this drawing an ellipse (or more) on a specific part of the picture and to get the coordinates (x; y) of its contour. I want to save these coordinates on a file, in order to use them later to see whether (or not) my data are inside this area.
This is my code:
import matplotlib.pyplot as plt
import numpy as np
from matplotlib.patches import Ellipse, Circle
from matplotlib.path import Path
# Get an example image
img = imread('sposa.png')
# Create a figure. Equal aspect so circles look circular
fig,ax = plt.subplots(1)
ax.set_aspect('equal')
# Show the image
ax.imshow(img)
ax.set_xlim(0,1600)
ax.set_ylim(0,1200)
# Now, loop through coord arrays, and create a circle at each x,y pair
ellipse = Ellipse((1000, 400), width=400, height=100, edgecolor='white',facecolor='none',linewidth=2)
ax.add_patch(ellipse)
path = ellipse.get_path()
# Show the image
plt.show()
When I run the code, I get this (that is exactly what I want):
However, when I print the path in order to check it, I get the following output, which (I suppose) is exclusively related to the ellipse.
Path(array([[ 0. , -1. ],
[ 0.2652031 , -1. ],
[ 0.51957987, -0.89463369],
[ 0.70710678, -0.70710678],
[ 0.89463369, -0.51957987],
[ 1. , -0.2652031 ],
[ 1. , 0. ],
[ 1. , 0.2652031 ],
[ 0.89463369, 0.51957987],
[ 0.70710678, 0.70710678],
[ 0.51957987, 0.89463369],
[ 0.2652031 , 1. ],
[ 0. , 1. ],
[-0.2652031 , 1. ],
[-0.51957987, 0.89463369],
[-0.70710678, 0.70710678],
[-0.89463369, 0.51957987],
[-1. , 0.2652031 ],
[-1. , 0. ],
[-1. , -0.2652031 ],
[-0.89463369, -0.51957987],
[-0.70710678, -0.70710678],
[-0.51957987, -0.89463369],
[-0.2652031 , -1. ],
[ 0. , -1. ],
[ 0. , -1. ]]), array([ 1, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4,
4, 4, 4, 4, 4, 4, 4, 4, 79], dtype=uint8))
However, I need a list of coordinates of the ellipse in relation to the pixel of the picture (1600 X 1200). I'm probably using the wrong function or there is something that does not match between the picture and the ellipse.
I should obtain something like this (this is an example from a previous experiment):
[ Path(array([[ 1599. , 868.86791294],
[ 1598. , 868.87197971],
[ 1597. , 868.8801087 ],
...,
[ 1597. , 675.30378536],
[ 1598. , 675.31373204],
[ 1599. , 675.31870792]]), None)]
665
Can anyone help me? Thank you in advance, R
回答1:
the path array appears to be a coarse normalized circle - I'd ignore it
you have the ellipse info alreadyellipse = Ellipse((1000, 400), width=400, height=100, ...)
I would just do a sin, cos paramaterized ellipse based on the 1st few numbers in Ellipse((1000, 400), width=400, height=100
which are the center point and axis lengths if you want to draw a hi res ellipse explicitly
for a membership test (x - x_0)^2/a^2 + (y - y_0)^2/b^2 <= 1
is probably best where a
, b
are 1/2 of the respective width=400, height=100
of course you would only need to test pixel indices within the bounding rectangle
回答2:
You should use Ellipse.get_path().vertices
, however it's not in the correct coordinates system. To transform it, apply ellipse.get_patch_transform().transform
to it. See below a working example
import matplotlib.pyplot as plt
from matplotlib.patches import Ellipse
from matplotlib.path import Path
from matplotlib.patches import PathPatch
img = plt.imread("image.jpg")
fig, ax = plt.subplots(1)
ax.set_aspect('equal')
ax.imshow(img)
# Create the base ellipse
ellipse = Ellipse((300, 300), width=400, height=100,
edgecolor='white', facecolor='none', linewidth=2)
# Get the path
path = ellipse.get_path()
# Get the list of path vertices
vertices = path.vertices.copy()
# Transform the vertices so that they have the correct coordinates
vertices = ellipse.get_patch_transform().transform(vertices)
# You can then save the vertices array to a file: csv, pickle... It's up to you
plt.show()
来源:https://stackoverflow.com/questions/48670760/draw-an-ellipse-on-a-figure-and-get-coordinates-python