问题
I have the following django model that contains JSONField:
class RatebookDataEntry(models.Model):
data = JSONField(blank=True, default=[])
last_update = models.DateTimeField(auto_now=True)
class Meta:
verbose_name_plural = 'Ratebook data entries'
And data field contains this json:
{
"annual_mileage": 15000,
"description": "LEON DIESEL SPORT COUPE",
"body_style": "Coupe",
"range_name": "LEON",
"co2_gkm_max": 122,
"manufacturer_name": "SEAT"
}
Can I sort queryset by one of the data fields? This query doesn't work.
RatebookDataEntry.objects.all().order_by("data__manufacturer_name")
回答1:
As Julien mentioned ordering on JSONField
is not yet supported in Django. But it's possible via RawSQL using PostgreSQL functions for jsonb. In OP's case:
from django.db.models.expressions import RawSQL
RatebookDataEntry.objects.all().order_by(RawSQL("data->>%s", ("manufacturer_name",)))
回答2:
Since Django 1.11, django.contrib.postgres.fields.jsonb.KeyTextTransform can be used instead of RawSQL
from django.contrib.postgres.fields.jsonb import KeyTextTransform
qs = RatebookEntry.objects.all()
qs = qs.annotate(manufacturer_name=KeyTextTransform('manufacturer_name', 'data'))
qs = qs.order_by('manufacturer_name')
# or...
qs = qs.order_by('-manufacturer_name')
On Django 1.10, you'll have to subclass KeyTransform
yourself:
from django.contrib.postgres.fields.jsonb import KeyTransform
class KeyTextTransform(KeyTransform):
operator = '->>'
nested_operator = '#>>'
_output_field = TextField()
Note: the difference between KeyTransform
and KeyTextTransform
is that KeyTransform
will return the JSON representation of the object, whereas KeyTextTransform
will return the value of the object.
For example, if data
is {"test": "stuff"}
, KeyTextTransform
will return 'stuff'
, whereas KeyTransform
will return '"stuff"'
(which can be parsed by json.loads
)
回答3:
Following Daniil Ryzhkov answer and Eugene Prikazchikov comment, you should be able to sort ASC and DESC on JSON data fields without annotating your queryset, by using both RawSQL
and OrderBy
. Also, you can perform case insensitive sorting by adding LOWER
:
from django.db.models.expressions import RawSQL, OrderBy
RatebookDataEntry.objects.all().order_by(OrderBy(RawSQL("LOWER(data->>%s)", ("manufacturer_name",)), descending=True))
To compare integers fields, you can cast as integer:
RatebookDataEntry.objects.all().order_by(OrderBy(RawSQL("cast(data->>%s as integer)", ("annual_mileage",)), descending=True))
回答4:
This is an upcoming feature which has already been added and will be released in Django 2.1, expected release of August 2018.
See https://code.djangoproject.com/ticket/24747 and https://github.com/django/django/pull/8528 for details.
回答5:
The documentation does not mention this possibility. It seems you cannot use order_by based on a JSONfield for the moment.
回答6:
I had to do the following to order by date (using to_date
). Assuming there's another value in data
called created_date
(e.g. 03.06.2019).
RatebookDataEntry.objects.all().order_by(
OrderBy(
RawSQL("to_date(values->>%s, 'DD.MM.YYYY')", ("created_date",)),
descending=True,
)
)
来源:https://stackoverflow.com/questions/36641759/django-1-9-jsonfield-order-by