问题
I have a class which returns json
[{
'title': 'Test Blog Title 1',
'content': 'Blog Content',
'author_name': 'User 1'
},
{
'title': 'Test Blog Title 2',
'content': 'Blog Content 2',
'author_name': 'User 2'
}]
I want to create Tastypie Model Resource based on the returned Json
I tried the Below Url this worked but i dont want to declare fields it should be dynamic
http://thehungrycoder.com/python/using-non-orm-data-sources-with-tastypie-in-django.html
class BlogResource(Resource):
#i dont want the fields below instead want it to be dynamic based on json
title = fields.CharField(attribute='title')
content = fields.CharField(attribute='content')
author = fields.CharField(attribute='author_name')
class Meta:
resource_name = 'blogs'
回答1:
If you' don't declare fields, they won't be accessible in the bundle. However, they'll always be accessible in the request.
You'll need to have at least one predefined field, to be used as a primary key. While you don't explicitly need to create it, you should have a way of knowing what object to return if the user issues a GET request for some object.
来源:https://stackoverflow.com/questions/15739287/dynamic-models-in-tastypie