问题
I have a problem with generating rr:termType rr:IRI in Virtuoso. I don't know if am I doing it wrong but I followed the W3C specification.
My mapping looks like this. When I generate triples with CONSTRUCT statement I still get "URL" but not IRI => <url> (OWNER_LINK and BRAND_LINK columns). Is it something Virtuoso doesn't support or am I coding it the wrong way?
DB.DBA.TTLP
( '
@prefix rr: <http://www.w3.org/ns/r2rml#> .
@prefix foaf: <http://xmlns.com/foaf/0.1/> .
@prefix gr: <http://purl.org/goodrelations/v1#> .
@prefix s: <http://schema.org/> .
@prefix pod: <http://linked.opendata.cz/ontology/product-open-data.org#> .
<#TriplesMap3>
a rr:TriplesMap ;
rr:logicalTable
[
rr:tableSchema "POD" ;
rr:tableOwner "DBA" ;
rr:tableName "BRAND_OWNER_BSIN"
];
rr:subjectMap
[
rr:template "http://linked.opendata.cz/resource/brand-owner-bsin/{BSIN}" ;
rr:class gr:BusinessEntity ;
rr:graph <http://linked.opendata.cz/resource/dataset/product-open-data.org/2014-01-01>
];
rr:predicateObjectMap
[
rr:predicate gr:hasBrand ;
rr:objectMap
[
rr:parentTriplesMap <#TriplesMap4> ;
rr:joinCondition
[
rr:child "OWNER_CD" ;
rr:parent "OWNER_CD" ;
]; ]; ];
.
<#TriplesMap4>
a rr:TriplesMap ;
rr:logicalTable
[
rr:tableSchema "POD" ;
rr:tableOwner "DBA" ;
rr:tableName "BRAND_OWNER"
];
rr:subjectMap
[
rr:template "http://linked.opendata.cz/resource/brand-owner/{OWNER_CD}" ;
rr:class gr:BusinessEntity ;
rr:graph <http://linked.opendata.cz/resource/dataset/product-open-data.org/2014-01-01>
];
rr:predicateObjectMap
[
rr:predicate gr:legalName ;
rr:objectMap
[ rr:column "OWNER_NM" ];
];
rr:predicateObjectMap
[
rr:predicate s:url ;
rr:objectMap
[
rr:termType rr:IRI ;
rr:column {OWNER_LINK} ;
]; ];
rr:predicateObjectMap
[
rr:predicate gr:hasBrand ;
rr:objectMap
[
rr:parentTriplesMap <#TriplesMap3> ;
rr:joinCondition
[
rr:child "OWNER_CD" ;
rr:parent "OWNER_CD" ;
]; ]; ];
.
<#TriplesMap2>
a rr:TriplesMap;
rr:logicalTable
[
rr:tableSchema "POD";
rr:tableOwner "DBA";
rr:tableName "BRAND_TYPE"
];
rr:subjectMap
[
rr:template "http://linked.opendata.cz/resource/brand-type/{BRAND_TYPE_CD}" ;
rr:class gr:BusinessEntityType ;
rr:graph <http://linked.opendata.cz/resource/dataset/product-open-data.org/2014-01-01>
];
rr:predicateObjectMap
[
rr:predicate gr:name ;
rr:objectMap
[ rr:column "BRAND_TYPE_NM" ];
];
.
<#TriplesMap1>
a rr:TriplesMap;
rr:logicalTable
[
rr:tableSchema "POD" ;
rr:tableOwner "DBA" ;
rr:tableName "BRAND"
];
rr:subjectMap
[
rr:template "http://linked.opendata.cz/resource/brand/{BSIN}" ;
rr:class gr:Brand ;
rr:graph <http://linked.opendata.cz/resource/dataset/product-open-data.org/2014-01-01>
];
rr:predicateObjectMap
[
rr:predicate pod:bsin ;
rr:objectMap [ rr:column "BSIN" ] ;
];
rr:predicateObjectMap
[
rr:predicate gr:name ;
rr:objectMap [ rr:column "BRAND_NM" ] ;
];
rr:predicateObjectMap
[
rr:predicate s:url ;
rr:objectMap
[
rr:termType rr:IRI ;
rr:column "BRAND_LINK" ;
]; ];
rr:predicateObjectMap
[
rr:predicate gr:BusinessEntityType ;
rr:objectMap
[
rr:parentTriplesMap <#TriplesMap2> ;
rr:joinCondition
[
rr:child "BRAND_TYPE_CD" ;
rr:parent "BRAND_TYPE_CD" ;
]; ]; ];
.
',
'http://product-open-data.org/temp',
'http://product-open-data.org/temp'
);
exec ( 'sparql ' || DB.DBA.R2RML_MAKE_QM_FROM_G ('http://product-open-data.org/temp') );
回答1:
So I figured out my code was wrong it should be like this
rr:predicateObjectMap
[
rr:predicateMap
[
rr:constant s:url
];
rr:objectMap
[
rr:termType rr:IRI ;
rr:template "{BRAND_LINK}" ;
];
];.
and it's working
Thank you.
回答2:
To be clear — are you saying the R2RML mapping is loading successfully, but when running a SPARQL CONSTRUCT query, the rr:termType rr:IRI mapping is not being displayed in the result set?
As the docs indicate, only rr:sqlQuery is not currently supported ...
来源：https://stackoverflow.com/questions/26821813/virtuoso-r2rml-rriri-generating