问题
Am I going mad? I'm running this on x86_64.
#include <stdio.h>
#include <time.h>
#include <unistd.h>
int main(int argc, char *argv[])
{
printf("Clock: %f\n", clock() / (double)CLOCKS_PER_SEC);
sleep(1);
printf("Clock: %f\n", clock() / (double)CLOCKS_PER_SEC);
sleep(1);
printf("Clock: %f\n", clock() / (double)CLOCKS_PER_SEC);
return 0;
}
This prints
Clock: 0.002880
Clock: 0.002968
Clock: 0.003019
It clearly waits for a second at the sleep(1)
lines, but the output is clearly wrong.
If that doesn't work, is there a portable C alternative?
回答1:
I'm an idiot. clock()
returns processor time used.
回答2:
You can declare an variable
time_t t1,t2;
t1 = time(NULL);
sleep(1);
t2 = time(NULL);
You can debug and view the values of t1 and t2.
I think you can take an reference from http://www.cplusplus.com/reference/clibrary/ctime/time/
来源:https://stackoverflow.com/questions/13510758/time-h-clock-broken-on-os-x