getch(); does not pause the loop

问题

I have this piece of code for instance:

while(true){
    printf("looping");
    getch();
}

Instead of waiting for user input on each loop, the loop just continues without me; printing

loop
loop
loop

until I close the program.

Is there a better way to read a single character ? All i really want to do is to have the user input a 'y' or a 'n'

回答1:

Just use fgetc. I assume you're using this to break out of the loop, so to update your example:

#include <stdio.h>

char iput;

while(true){
    printf("looping");
    iput = fgetc(stdin);
    if(iput == 'n')
      break;
} 

回答2:

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
void main()
{
   while(1)
 {
   printf("\nlooping");
   char t=getch();
   if(t=='n')
   exit(0);
 }
}

回答3:

You can also use

fflush(stdin) 

before calling getch

regards

来源：https://stackoverflow.com/questions/12060572/getch-does-not-pause-the-loop