问题
I am writting a custom widget which I want to return a list as the value. From what I can find to set the value that is returned you create a custom value_from_datadict function. I have done this
def value_from_datadict(self, data, files, name):
value = data.get(name, None)
if value:
# split the sting up so that we have a list of nodes
tag_list = value.strip(',').split(',')
retVal = []
# loop through nodes
for node in tag_list:
# node string should be in the form: node_id-uuid
strVal = str(node).split("-")
uuid = strVal[-1]
node_id = strVal[0]
# create a tuple of node_id and uuid for node
retVal.append({'id': node_id, 'uuid': uuid})
if retVal:
# if retVal is not empty. i.e. we have a list of nodes
# return this. if it is empty then just return whatever is in data
return retVal
return value
I expect this to return a list but when I print out the value it is returned as a string rather than a list. The string itself contains the right text but as i said it is a string and not a list. An example of what is returned could be
[{'id': '1625', 'uuid': None}]
but if I did str[0] it would print out [ instead of {'id': '1625', 'uuid': None}
How can I stop it from converting my list into a string?
Thanks
回答1:
Well, it's simple: if you have a CharField
, then you will get a string as a result, because CharField
uses method to_python
, that coerces the result to string. You need to create your own Field
for this one and return a list.
OLD
Could you post the result of:
x = value_from_datadict(..)
print type(x)
so we can see, what exactly is returned?
And could you post the whole test case you are using to deliver the example?
来源:https://stackoverflow.com/questions/2325479/in-django-forms-custom-widget-return-list-as-value-instead-of-string