问题
How to provide Hibernate Search parameters when using Spring Boot?
...
spring.datasource.driverClassName=org.postgresql.Driver
hibernate.search.jmx_enabled=true
hibernate.search.default.directory_provider=filesystem
hibernate.search.generate_statistics=true
hibernate.search.lucene_version=LUCENE_CURRENT
hibernate.search.default.indexBase=/mypath-to-index
It does not care what I provide. Default settings always get applied.
I think below code does not have anything to process properties related to Hibernate Search. Can that be the issue?
https://github.com/spring-projects/spring-boot/blob/master/spring-boot-autoconfigure/src/main/java/org/springframework/boot/autoconfigure/orm/jpa/JpaProperties.java
回答1:
You can put them in the application.properties file if you put "spring.jpa.properties." in front of the property names.
Example:
spring.jpa.properties.hibernate.search.jmx_enabled=true
spring.jpa.properties.hibernate.search.default.directory_provider=filesystem
spring.jpa.properties.hibernate.search.generate_statistics=true
spring.jpa.properties.hibernate.search.lucene_version=LUCENE_CURRENT
spring.jpa.properties.hibernate.search.default.indexBase=/mypath-to-index
Spring will take any properties under spring.jpa.properties.* and pass them along (with the prefix stripped) once the EntityManagerFactory is created.
回答2:
Got it working.
Put another property file named "hibernate.properties" inside src/main/resources with below content.
hibernate.search.jmx_enabled=true
hibernate.search.default.directory_provider=filesystem
hibernate.search.generate_statistics=true
hibernate.search.lucene_version=LUCENE_CURRENT
hibernate.search.default.indexBase=/mypath-to-index
来源：https://stackoverflow.com/questions/55801790/spring-boot-creating-hibernate-search-class-for-initial-lucene-index