问题
I get an error while writing the IIF stamtement, table and the statement given below,
Statement:
SELECT IIF(EMP_ID=1,'True','False') from Employee;
Error: 00907-missing right parantheses
CREATE TABLE SCOTT.EMPLOYEE
(
EMP_ID INTEGER NOT NULL,
EMP_FNAME VARCHAR2(30 BYTE) NOT NULL,
EMP_LNAME VARCHAR2(30 BYTE) NOT NULL,
EMP_ADDRESS VARCHAR2(50 BYTE) NOT NULL,
EMP_PHONE CHAR(10 BYTE) NOT NULL,
EMP_GENDER CHAR(1 BYTE)
)
Please provide your inputs.
回答1:
Oracle doesn't provide such IIF Function. Instead, try using one of the following alternatives:
DECODE Function:
SELECT DECODE(EMP_ID, 1, 'True', 'False') from Employee
CASE Function:
SELECT CASE WHEN EMP_ID = 1 THEN 'True' ELSE 'False' END from Employee
回答2:
Two other alternatives:
a combination of NULLIF and NVL2. You can only use this if
emp_id
isNOT NULL
, which it is in your case:select nvl2(nullif(emp_id,1),'False','True') from employee;
simple CASE expression (Mt. Schneiders used a so-called searched
CASE
expression)select case emp_id when 1 then 'True' else 'False' end from employee;
回答3:
In PL/SQL, there is a trick to use the undocumented OWA_UTIL.ITE
function.
SET SERVEROUTPUT ON
DECLARE
x VARCHAR2(10);
BEGIN
x := owa_util.ite('a' = 'b','T','F');
dbms_output.put_line(x);
END;
/
F
PL/SQL procedure successfully completed.
来源:https://stackoverflow.com/questions/14791684/oracle-iif-statement