问题
I am trying to get the IP Address using NSHost. With the NSHost object I can use the addresses method to access an array of objects one of which is the IP Address. I fear though that the IP Address may change position in the array from one machine to the other. Is there a way to access this information in a universal way?
There was an attempt to answer this question in a previous post, but as you can see it falls short.
IP Address? - Cocoa
Here is my code:
+(NSString *) ipAddress {
NSHost * h = [[[NSHost currentHost] addresses] objectAtIndex:1];
return h ;
}
回答1:
I have used this on many machines without problems.
-(void) getIPWithNSHost{
NSArray *addresses = [[NSHost currentHost] addresses];
for (NSString *anAddress in addresses) {
if (![anAddress hasPrefix:@"127"] && [[anAddress componentsSeparatedByString:@"."] count] == 4) {
stringAddress = anAddress;
break;
} else {
stringAddress = @"IPv4 address not available" ;
}
}
//NSLog (@"getIPWithNSHost: stringAddress = %@ ",stringAddress);
}
NSString *stringAddress; is declared else where
回答2:
The only thing I can think of is to use something like "http://www.dyndns.org/cgi-bin/check_ip.cgi" others may have a better way.
This is an example,(i.e a quick cobbled together code)
NSUInteger an_Integer;
NSArray * ipItemsArray;
NSString *externalIP;
NSURL *iPURL = [NSURL URLWithString:@"http://www.dyndns.org/cgi-bin/check_ip.cgi"];
if (iPURL) {
NSError *error = nil;
NSString *theIpHtml = [NSString stringWithContentsOfURL:iPURL
encoding:NSUTF8StringEncoding
error:&error];
if (!error) {
NSScanner *theScanner;
NSString *text = nil;
theScanner = [NSScanner scannerWithString:theIpHtml];
while ([theScanner isAtEnd] == NO) {
// find start of tag
[theScanner scanUpToString:@"<" intoString:NULL] ;
// find end of tag
[theScanner scanUpToString:@">" intoString:&text] ;
// replace the found tag with a space
//(you can filter multi-spaces out later if you wish)
theIpHtml = [theIpHtml stringByReplacingOccurrencesOfString:
[ NSString stringWithFormat:@"%@>", text]
withString:@" "] ;
ipItemsArray =[theIpHtml componentsSeparatedByString:@" "];
an_Integer=[ipItemsArray indexOfObject:@"Address:"];
externalIP =[ipItemsArray objectAtIndex: ++an_Integer];
}
NSLog(@"%@",externalIP);
} else {
NSLog(@"Oops... g %d, %@",
[error code],
[error localizedDescription]);
}
}
[pool drain];
return 0;}
回答3:
I wanted to update my original answer on getting an external ip.
There is not much change but I wanted to show how to get and parse the HTML with use NSXMLDocument and Xquary
This also gives a small illustration of how you can parse HTML by getting the nodes. Which in my opinion is more straight forward. Although NSXMLDocument is initially for XML it will parse the HTML DOM tree
NSString *externalIP;
///--DYNDNS.ORG URL
NSURL *iPURL = [NSURL URLWithString:@"http://www.dyndns.org/cgi-bin/check_ip.cgi"];
if (iPURL) {
NSError *err_p = nil;
//--use NSXMLDocument to get the url:(*Requests NSXMLNode to preserve whitespace characters (such as tabs and carriage returns) in the XML source that are not part of node content*)
NSXMLDocument * xmlDoc = [[NSXMLDocument alloc] initWithContentsOfURL:iPURL
options:(NSXMLNodePreserveWhitespace|
NSXMLNodePreserveCDATA)
error:&err_p];
if (xmlDoc == nil) {
//-- That did not work so lets see if we can change the malformed XML into valid XML during processing of the document.
xmlDoc = [[NSXMLDocument alloc] initWithContentsOfURL:iPURL
options:NSXMLDocumentTidyXML
error:&err_p];
}
if (!err_p) {
NSError * error;
//-- We will use XQuary to get the text from the child node. Dyndns.org page is very simple. So we just need to get the Body text.
NSString *xpathQueryTR = @"//body/text()";
//-- we get the first node's string value. We use string value to in effect cast to NSString.
//We the seperate the string into components using a space. and obtain the last object in the returned array.
//--This gives us the IP string without the "Current IP Address:" string.
externalIP = [[[[[xmlDoc nodesForXPath:xpathQueryTR error:&error]objectAtIndex:0] stringValue]componentsSeparatedByString:@" "]lastObject];
if (!error) {
NSLog(@"%@",externalIP);
}else {
NSLog(@"Oops... g %ld, %@",
(long)[error code],
[error localizedDescription]);
}
}else {
NSLog(@"Oops... g %ld, %@",
(long)[err_p code],
[err_p localizedDescription]);
}
}
回答4:
Made an utility class to find the IP addresses. Minimalistic approach. You can robustify it with more conditions or regex checking.
NSLog(@"Addresses: %@", [[NSHost currentHost] addresses]);
This is the list returned by NSHost
"fe80::1610:9fff:fee1:8c2f%en0",
"192.168.212.61",
"fe80::2829:3bff:fee6:9133%awdl0",
"fe80::e54b:8494:bbc8:3989%utun0",
"fd68:cc16:fad8:ded9:e54b:8494:bbc8:3989",
"10.11.51.61",
"::1",
"127.0.0.1",
"fe80::1%lo0"
Test method,
- (void)testHost {
NSLog(@"Addresses: %@", [[NSHost currentHost] addresses]);
for (NSString *s in [[NSHost currentHost] addresses]) {
IPAddress *addr = [[IPAddress alloc] initWithString:s];
if (![addr isLocalHost] && [addr isIPV4]) {
// do something
}
}
}
IPAddress.h
#import <Foundation/Foundation.h>
@interface IPAddress : NSObject
@property (nonatomic, strong) NSString *IPAddress;
- (id)initWithString:(NSString *)ipaddress;
- (BOOL)isLocalHost;
- (BOOL) isIPV4;
- (BOOL) isIPV6;
@end
IPAddress.m
#import "IPAddress.h"
@implementation IPAddress
- (id)initWithString:(NSString *)ipaddress {
self = [super init];
if (self) {
self.IPAddress = ipaddress;
}
return self;
}
- (BOOL)isLocalHost {
if (self.IPAddress == nil) return NO;
if ([@"127.0.0.1" compare:self.IPAddress options:NSCaseInsensitiveSearch] == NSOrderedSame) {
return YES;
}
if ([@"localhost" compare:self.IPAddress options:NSCaseInsensitiveSearch] == NSOrderedSame) {
return YES;
}
if ([@"::1" compare:self.IPAddress options:NSCaseInsensitiveSearch] == NSOrderedSame) {
return YES;
}
return NO;
}
- (BOOL) isIPV4 {
NSArray *ar = [self.IPAddress componentsSeparatedByString:@"."];
if (ar.count == 4) {
return YES;
}
return NO;
}
- (BOOL) isIPV6 {
if (![self isIPV4]) {
if ([self.IPAddress rangeOfString:@":"].location != NSNotFound) {
return YES;
}
}
return NO;
}
@end
回答5:
As the answers to the question you mention above have said, there are a variety of IP addresses that a single machine can have. If that is what you want, then you might be better off using the names method of NSHost to get an array of names, which you can then filter for the suffix (i.e *.lan) to get the name of the host you want with this name. In my case. the .lan address returns my network ip address as a dotted quad.
If you want to find the external ip address, then this is a good answer to look at.
回答6:
My first Answer is to supply the Private IP address assigned to the Machine on private network from say your router.
If you want to see the public IP, which is the one facing the internet. Normally assigned by your service provider. You may want to look at the answer by Jim Dovey --> here
I tested it and it worked well, but read the rest of the comments and answers which point to ambiguities in trying to get a public IP.
回答7:
You can create a category on NSHost and do something like this:
#import <arpa/inet.h>
#import <ifaddrs.h>
#import <net/if.h>
.h
+ (NSDictionary *) interfaceIP4Addresses;
+ (NSDictionary *) interfaceIP6Addresses;
+ (NSDictionary *) interfaceIPAddresses;
.m
typedef NS_ENUM(NSUInteger, AddressType) {
AddressTypeBoth = 0,
AddressTypeIPv4 = 1,
AddressTypeIPv6 = 2
};
@implementation SomeClass
#pragma mark - Helper Methods:
+ (NSDictionary *) _interfaceAddressesForFamily:(AddressType)family {
NSMutableDictionary *interfaceInfo = [NSMutableDictionary dictionary];
struct ifaddrs *interfaces;
if ( (0 == getifaddrs(&interfaces)) ) {
struct ifaddrs *interface;
for ( interface=interfaces; interface != NULL; interface=interface->ifa_next ) {
if ( (interface->ifa_flags & IFF_UP) && !(interface->ifa_flags & IFF_LOOPBACK) ) {
const struct sockaddr_in *addr = (const struct sockaddr_in *)interface->ifa_addr;
if ( addr && addr->sin_family == PF_INET ) {
if ( (family == AddressTypeBoth) || (family == AddressTypeIPv4) ) {
char ip4Address[INET_ADDRSTRLEN];
inet_ntop( addr->sin_family, &(addr->sin_addr), ip4Address, INET_ADDRSTRLEN );
[interfaceInfo setObject:[NSString stringWithUTF8String:interface->ifa_name]
forKey:[NSString stringWithUTF8String:ip4Address]];
} } else if ( addr && addr->sin_family == PF_INET6 ) {
if ( (family == AddressTypeBoth) || (family == AddressTypeIPv6) ) {
char ip6Address[INET6_ADDRSTRLEN];
inet_ntop( addr->sin_family, &(addr->sin_addr), ip6Address, INET6_ADDRSTRLEN );
[interfaceInfo setObject:[NSString stringWithUTF8String:interface->ifa_name]
forKey:[NSString stringWithUTF8String:ip6Address]];
} }
}
} freeifaddrs( interfaces );
} return [NSDictionary dictionaryWithDictionary:interfaceInfo];
}
#pragma mark - Class Methods:
+ (NSDictionary *) interfaceIP4Addresses { return [self _interfaceAddressesForFamily:AddressTypeIPv4]; }
+ (NSDictionary *) interfaceIP6Addresses { return [self _interfaceAddressesForFamily:AddressTypeIPv6]; }
+ (NSDictionary *) interfaceIPAddresses { return [self _interfaceAddressesForFamily:AddressTypeBoth]; }
@end
This works really fast and well. If you need other info or to monitor then use System Configuration framework.
来源：https://stackoverflow.com/questions/3266428/accessing-ip-address-with-nshost