Python: Flatten a list of Objects

问题

I have a list of Objects and each object has inside it a list of other object type. I want to extract those lists and create a new list of the other object.

List1:[Obj1, Obj2, Obj3]

Obj1.myList = [O1, O2, O3]
Obj2.myList = [O4, O5, O6]
Obj3.myList = [O7, O8, O9]

I need this:

L = [O1, O2, O3, O4, ...., O9];

I tried extend() and reduce() but didn't work

bigList = reduce(lambda acc, slice: acc.extend(slice.coresetPoints.points), self.stack, [])

P.S.

Looking for python flatten a list of list didn't help as I got a list of lists of other object.

回答1:

using itertools.chain (or even better in that case itertools.chain.from_iterable as niemmi noted) which avoids creating temporary lists and using extend

import itertools
print(list(itertools.chain(*(x.myList for x in List1))))

or (much clearer and slightly faster):

print(list(itertools.chain.from_iterable(x.myList for x in List1)))

small reproduceable test:

class O:
    def __init__(self):
        pass

Obj1,Obj2,Obj3 = [O() for _ in range(3)]

List1 = [Obj1, Obj2, Obj3]

Obj1.myList = [1, 2, 3]
Obj2.myList = [4, 5, 6]
Obj3.myList = [7, 8, 9]

import itertools
print(list(itertools.chain.from_iterable(x.myList for x in List1)))

result:

[1, 2, 3, 4, 5, 6, 7, 8, 9]

回答2:

You can achieve that with one-line list comprehension:

[i for obj in List1 for i in obj.myList]

回答3:

list.extend() returns None, not a list. You need to use concatenation in your lambda function, so that the result of the function call is a list:

bigList = reduce(lambda x, y: x + y.myList, List1, [])

While this is doable with reduce(), using a list comprehension would be both faster and more pythonic:

bigList = [x for obj in List1 for x in obj.myList]

回答4:

Not exactly rocket science:

L = []
for obj in List1:
    L.extend(obj.myList)

来源：https://stackoverflow.com/questions/41521431/python-flatten-a-list-of-objects