What Does Adding One to a Character Array in C Do?

问题

I'm looking through some code for learning purposes. I'm working through this portion of code.

// e.g. const unsigned char data={0x1,0x7C ... }
unsigned char buf[40];
memset(buf,0,40);
buf[0] = 0x52;
memcpy(buf+1, data, length); // What does buf+1 do in this situation?

On the last line where memcpy is called what does buf+1 do? buf is a character array, so what does +1 do to it?

回答1:

In C, every array name is a pointer, so buf here also means the pointer which point to buf[0].Then "buf+1" means "buf[1]"'s address.

回答2:

buf+1 is equivalent to &(buf[1])

回答3:

buf+1 is the same as &(buf[1]). In other words, it returns a pointer to the 2nd (index 1) character of buf.

回答4:

Pointer Arithmetic (Stack Overflow)

来源：https://stackoverflow.com/questions/1391583/what-does-adding-one-to-a-character-array-in-c-do