问题
I'm using Django and Tastypie to create a RESTful web app. I have a model like this
class Picture(models.Model):
# some other fields
image = models.ImageField('Image')
def image_url(self):
return self.image.url
Tastypie will give the image's path but actually I need its url. How to write a correct resource api to achive this?
回答1:
By default TastyPie is supposed to return URL of ImageField and FileField. See here: https://github.com/toastdriven/django-tastypie/blob/master/tastypie/fields.py#L185
# Try to return the URL if it's a ``File``, falling back to the string
# itself if it's been overridden or is a default.
return getattr(value, 'url', value)
Please make sure that you are using the latest version of TastyPie.
来源:https://stackoverflow.com/questions/10153355/how-to-make-tastypie-give-the-url-of-a-file-instead-of-its-path