How to return two fields from a subquery

时光怂恿深爱的人放手 提交于 2019-12-11 05:05:53

问题


The query below works, but I would like to know if there is a better way to do it.

There is one subquery that uses two subqueries. The two subqueries are identical but return two different fields. Is there a way to use only one subquery that returns two fields?

I checked similar questions (this, this and this), but I don't think they apply in this case.

Here is the query:

SELECT *,
       time(strftime('%s', EndTime) - strftime('%s', StartTime), 'unixepoch') AS Duration
  FROM (
           SELECT (
                      SELECT Time
                        FROM Log AS LogStart
                       WHERE LogStart.User = Log.User AND 
                             LogStart.Time <= Log.Time AND 
                             LogStart.[Action] != 'done'
                       ORDER BY LogStart.Time DESC
                       LIMIT 1
                  )
                  AS StartTime,
                  Time AS EndTime,
                  User,
                  (
                      SELECT [Action]
                        FROM Log AS LogStart
                       WHERE LogStart.User = Log.User AND 
                             LogStart.Time <= Log.Time AND 
                             LogStart.[Action] != 'done'
                       ORDER BY LogStart.Time DESC
                       LIMIT 1
                  )
                  AS [Action]
             FROM Log
            WHERE [Action] = 'done'
       )
 ORDER BY duration DESC;

Here is some test data:

CREATE TABLE Log (
    Time     DATETIME,
    User     CHAR,
    [Action] CHAR
);

insert into Log values('2017-01-01 10:00:00', 'Joe', 'Play');
insert into Log values('2017-01-01 10:01:00', 'Joe', 'done');
insert into Log values('2017-01-01 10:02:00', 'Joe', 'Sing');
insert into Log values('2017-01-01 10:03:00', 'Joe', 'done');
insert into Log values('2017-01-01 10:04:00', 'Ann', 'Play');
insert into Log values('2017-01-01 10:04:30', 'Bob', 'Action without corresponding "done" which must be ignored');
insert into Log values('2017-01-01 10:05:00', 'Joe', 'Play');
insert into Log values('2017-01-01 10:06:00', 'Ann', 'done');
insert into Log values('2017-01-01 10:07:00', 'Joe', 'done');
insert into Log values('2017-01-01 10:08:00', 'Ann', 'Play');
insert into Log values('2017-01-01 10:09:00', 'Ann', 'done');

回答1:


Use a self join... I don't have SQLLite, so the syntax may be off here, but you should get the idea...

Select e.*, time(strftime('%s', e.[Time]) - 
           strftime('%s', s.[Time]), 'unixepoch') AS Duration
From log e join log s  -- s is for the startevent; e for end event
    on s.[User] = e.[User]
       and s.[Action] != 'done'
       and e.[Action] = 'done'
       and s.[Time] = 
          (Select Max([time] from log
           where [User] = e.[User]
                   and [time] <= e.[Time]
                   and [Action] != 'done')



回答2:


I made this: is what you were looking for? (MSSQL, but I think should work in SQLLite as there are not "non standard" SQL commands; I should write USER inside []).

SELECT STARTTIME, MIN(ENDTIME) AS ENDTIME, [USER], ACTION 
FROM (
SELECT B.TIME AS STARTTIME, A.TIME AS ENDTIME, A.[USER], B.ACTION
FROM LOG A
INNER JOIN (SELECT * FROM LOG) B ON A.[USER]= B.[USER] AND B.ACTION<>'done' AND B.TIME< A.TIME
WHERE A.Action='done'
) X 
GROUP BY X.STARTTIME, [USER], ACTION ;

Output:

STARTTIME               ENDTIME                 USER       ACTION
----------------------- ----------------------- ---------- ---------------------
2017-01-01 10:00:00.000 2017-01-01 10:01:00.000 Joe        Play
2017-01-01 10:02:00.000 2017-01-01 10:03:00.000 Joe        Sing
2017-01-01 10:04:00.000 2017-01-01 10:06:00.000 Ann        Play
2017-01-01 10:05:00.000 2017-01-01 10:07:00.000 Joe        Play
2017-01-01 10:08:00.000 2017-01-01 10:09:00.000 Ann        Play

With only your data, compared execution plan in MSSQL showed that your query "costs" 87% while this latter costs 13% (their sum is - of course - 100%)



来源:https://stackoverflow.com/questions/42766634/how-to-return-two-fields-from-a-subquery

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