问题
If a particular String contains a newline character that is invisible (not \n but is 0A in hexadecimal because this value is passed down from the database), how can i able to chomp it away? Will Apache Chomp help?
http://commons.apache.org/lang/api-2.5/org/apache/commons/lang/StringUtils.html#chomp(java.lang.String)
The hex form of the text returned from the database is "5761 6920 4D61 6E0D 0A"
It translates to "Wai Man" with a carriage return.
回答1:
You can use a regular expression
String text = "Hello\r\nThere\r\n";
String shortText = text.replaceAll("\r", "");
来源:https://stackoverflow.com/questions/6870858/java-how-to-remove-carriage-return-hex-0a-from-string