问题
I am trying to get the student that scored highest on the final exam
first I select
SELECT s.STUDENT_ID, w.LAST_NAME,w.FIRST_NAME, MAX(s.NUMERIC_GRADE) AS NUMERIC_FINAL_GRADE
FROM GRADE s , SECTION z, STUDENT w
WHERE s.SECTION_ID = z.SECTION_ID AND s.STUDENT_ID = w.STUDENT_ID
AND z.COURSE_NO = 230 AND z.SECTION_ID = 100 AND s.GRADE_TYPE_CODE = 'FI'
GROUP BY s.STUDENT_ID, w.FIRST_NAME,w.LAST_NAME
and it gives me this result and that is what I want
STUDENT_ID LAST_NAME FIRST_NAME NUMERIC_FINAL_GRADE
---------- ------------------------- ------------------------- -------------------
262 Walston Donna 85
141 Boyd Robert 84
but when I try to get the max from these two it gives me no rows or an error
i.STUDENT_ID, k.LAST_NAME,k.FIRST_NAME
FROM GRADE i , SECTION j, STUDENT k
WHERE i.SECTION_ID = j.SECTION_ID AND i.STUDENT_ID = k.STUDENT_ID
AND j.COURSE_NO = 230 AND j.SECTION_ID = 100 AND i.GRADE_TYPE_CODE = 'FI'
GROUP BY i.STUDENT_ID, k.FIRST_NAME,k.LAST_NAME
HAVING COUNT(*) =
(SELECT MAX(NUMERIC_FINAL_GRADE)
FROM
(SELECT s.STUDENT_ID, w.LAST_NAME,w.FIRST_NAME, MAX(s.NUMERIC_GRADE) AS NUMERIC_FINAL_GRADE
FROM GRADE s , SECTION z, STUDENT w
WHERE s.SECTION_ID = z.SECTION_ID AND s.STUDENT_ID = w.STUDENT_ID
AND z.COURSE_NO = 230 AND z.SECTION_ID = 100 AND s.GRADE_TYPE_CODE = 'FI'
GROUP BY s.STUDENT_ID, w.FIRST_NAME,w.LAST_NAME))
ORDER BY i.STUDENT_ID, k.LAST_NAME,k.FIRST_NAME;
How can I get max result from these two results that I already have and why does it give me no rows or an error ?
回答1:
The traditional method is an analytic MAX() (or other analytic function):
select *
from ( select s.student_id
, w.last_name
, w.first_name
, s.numeric_grade
, max(s.numeric_grade) over () as numeric_final_grade
from grade s
join section z
on s.section_id = z.section_id
join student w
on s.student_id = w.student_id
where z.course_no = 230
and z.section_id = 100
and s.grade_type_code = 'FI'
)
where numeric_grade = numeric_final_grade
But I would probably prefer using FIRST (KEEP).
select max(s.student_id) keep (dense_rank first order by s.numeric_grade desc) as student_id
, max(w.last_name) keep (dense_rank first order by s.numeric_grade desc) as last_name
, max(w.first_name) keep (dense_rank first order by s.numeric_grade desc) as first_na,e
, max(s.numeric_grade_name) as numeric_final_grade
from grade s
join section z
on s.section_id = z.section_id
join student w
on s.student_id = w.student_id
where z.course_no = 230
and z.section_id = 100
and s.grade_type_code = 'FI'
The benefits of both of these approaches over what you initially suggest is that you only scan the table once, there's no need to access either the table or the index a second time. I can highly recommend Rob van Wijk's blog post on the differences between the two.
P.S. these will return different results, so they are slightly different. The analytic function will maintain duplicates were two students to have the same maximum score (this is what your suggestion will do as well). The aggregate function will remove duplicates, returning a random record in the event of a tie.
回答2:
SELECT * FROM
(
SELECT s.STUDENT_ID, w.LAST_NAME,w.FIRST_NAME,
MAX(s.NUMERIC_GRADE) AS NUMERIC_FINAL_GRADE
FROM GRADE s, SECTION z, STUDENT w
WHERE s.SECTION_ID = z.SECTION_ID
AND s.STUDENT_ID = w.STUDENT_ID
AND z.COURSE_NO = 230 AND z.SECTION_ID = 100
AND s.GRADE_TYPE_CODE = 'FI'
GROUP BY s.STUDENT_ID, w.FIRST_NAME, w.LAST_NAME
ORDER BY MAX(s.NUMERIC_GRADE)
) AS M
WHERE ROWNUM <= 1
来源:https://stackoverflow.com/questions/19435503/subquery-getting-the-highest-score