问题
For an online calculator where users may enter an energy amount to calculate corresponding fees, I need the PHP script to accept various user inputs. The value of "2 million and one fourth joule" may be entered as:
2000000.25 (default notation)
2,000,000.25 (with thousands separator)
2000000,25 (comma as decimal point)
2.000.000,25 (comma as decimal point, with thousands separator)
2'000'000.25 (alternative format)
2 000 000,25 (French notation)
How could I make the script aware of such differences?
My first try was to just str_replace alternative characters with the default ones, but the period (.) may be either a decimal or a thousands separator. I tried using sscanf but how can I make sure that it reads the number correctly?
Most users will only provide two digits after the decimal point, but is there any way I can distinguish 1.234 (1 point 234, period as decimal separator) and 1.234 (one thousand two hundred thirty-four, period as thousands separator)?
回答1:
There's no way to know what 1.234 means.
- decide on a decimal separator
- replace the last
,or.with that separator - only allow one separator
- limit the input to numeric values,
,and.
回答2:
Since I wasn't able to find a simple solution via some built-in PHP functions, I wrote two functions to (1) check if the entered string may be a number at all and (2) if it is well-formed depending on the separators used.
I restricted the possible separators to period (.), comma (,), space () and apostrophe (') as thousands separators. The decimal point may only be one of the first two options. Both sets of separators can be edited to allow even more or restrict the ones in place.
What I am actually doing is to look for all number columns and all separators by using a couple of simple preg_match_all calls.
The complete code reads as follows and should be self-explaining as I added some comments when throwing a false. I'm sure, this can be simplified somehow, but it works right now and filters many errors while allowing even some strange combinations such as 2 000 000.25 or 2'000'000,25.
function check_number($number) {
if ((int) substr($number,0,1) == 0) {
return false; // not starting with a digit greater than 0
}
if ((string) substr($number,-1) != "0" && (int) substr($number,-1) == 0) {
return false; // not ending with a digit
}
preg_match_all('/([^0-9]{2,})/', $number, $sep, PREG_PATTERN_ORDER);
if (isset($sep[0][0])) {
return false; // more than one consecutive non-digit character
}
preg_match_all('/([^0-9]{1})/', $number, $sep, PREG_PATTERN_ORDER);
if (count($sep[0]) > 2 && count(array_unique($sep[0])) > 2) {
return false; // more than 2 different separators
}
elseif (count($sep[0]) > 2) {
$last_sep = array_pop($sep[0]);
if (!in_array($last_sep,array(".",","))) {
return false; // separator not allowed as last one
}
$sep_unique = array_unique($sep[0]);
if (count($sep_unique) > 1) {
return false; // not all separators (except last one) are identical
}
elseif (!in_array($sep_unique[0],array("'",".",","," "))) {
return false; // separator not allowed
}
}
return true;
}
function convert_number($number) {
preg_match_all('/([0-9]+)/', $number, $num, PREG_PATTERN_ORDER);
preg_match_all('/([^0-9]{1})/', $number, $sep, PREG_PATTERN_ORDER);
if (count($sep[0]) == 0) {
// no separator, integer
return (int) $num[0][0];
}
elseif (count($sep[0]) == 1) {
// one separator, look for last number column
if (strlen($num[0][1]) == 3) {
if (strlen($num[0][0]) <= 3) {
// treat as thousands seperator
return (int) ($num[0][0] * 1000 + $num[0][1]);
}
elseif (strlen($num[0][0]) > 3) {
// must be decimal point
return (float) ($num[0][0] + $num[0][1] / 1000);
}
}
else {
// must be decimal point
return (float) ($num[0][0] + $num[0][1] / pow(10,strlen($num[0][1])));
}
}
else {
// multiple separators, check first an last
if ($sep[0][0] == end($sep[0])) {
// same character, only thousands separators, check well-formed nums
$value = 0;
foreach($num[0] AS $p => $n) {
if ($p == 0 && strlen($n) > 3) {
return -1; // malformed number, incorrect thousands grouping
}
elseif ($p > 0 && strlen($n) != 3) {
return -1; // malformed number, incorrect thousands grouping
}
$value += $n * pow(10, 3 * (count($num[0]) - 1 - $p));
}
return (int) $value;
}
else {
// mixed characters, thousands separators and decimal point
$decimal_part = array_pop($num[0]);
$value = 0;
foreach($num[0] AS $p => $n) {
if ($p == 0 && strlen($n) > 3) {
return -1; // malformed number, incorrect thousands grouping
}
elseif ($p > 0 && strlen($n) != 3) {
return -1; // malformed number, incorrect thousands grouping
}
$value += $n * pow(10, 3 * (count($num[0]) - 1 - $p));
}
return (float) ($value + $decimal_part / pow(10,strlen($decimal_part)));
}
}
}
I am aware of one flaw this set of function has: 1.234 or 1,234 will always be treated as the whole number 1234, as the function assumes the separator must be a thousands separator if there are less than 4 digits in front of the single separator.
来源：https://stackoverflow.com/questions/13512936/accepting-international-numbers-with-decimal-and-thousands-separator-in-php