How can I get information about the file that launched my app?

问题

Similar to How to get the arguments for opening file with electron app but the solution there is not working for me.

Using:
OS - Windows 10
Electron - https://github.com/castlabs/electron-releases.git#v1.8.7-vmp1010
electron-builde - v20.28.3

I have a an electron app build with electron-builder, and using the latter I have specified a custom file association, .custom.

So when you double-click on a file with this extension, file.custom, the installed app opens. This file would have some data in it that the app needs, and I'd like to read this data using my app.

Is there any way that my app can detect what launched it, so that I can say "file.custom" launched me, and it's sitting at "C:\Users\Owner\Downloads\,?

The file does not appear in process.argv

回答1:

You can get a reference to the file using process.argv, example:

var ipc = require('ipc');
var fs = require('fs');

// read the file and send data to the render process
ipc.on('get-file-data', function(event) {
    var data = null;
    if (process.platform == 'win32' && process.argv.length >= 2) {
        var openFilePath = process.argv[1];
        data = fs.readFileSync(openFilePath, 'utf-8');
    }
    event.returnValue = data;
});

source: Source

来源：https://stackoverflow.com/questions/52194506/how-can-i-get-information-about-the-file-that-launched-my-app