原文:在论坛中出现的比较难的sql问题:33(递归 连续日期问题 )
最近,在论坛中,遇到了不少比较难的sql问题,虽然自己都能解决,但发现过几天后,就记不起来了,也忘记解决的方法了。
所以,觉得有必要记录下来,这样以后再次碰到这类问题,也能从中获取解答的思路。
MS-SQL取连续日期问题
http://bbs.csdn.net/topics/390635235?page=1#post-395995697
我现在需要得出表A中所有FBeginDate和FEndDate字段间的日期
下面是我的解法,使用了递归查询:
drop table tb create table tb(FBeginDate datetime,FEndDate datetime) insert into tbselect '2010-10-01','2010-10-01'union all select '2010-10-01','2010-10-07'union all select '2011-01-30','2011-02-12' ;with tas(select 1 as numberunion allselect number + 1from twhere t.number < 100) select tb.FBeginDate, tb.FEndDate, dateadd(day,t.number-1,FBeginDate) as '两个日期之间的天'from tbinner join t on datediff(day,FBeginDate,FEndDate) +1 >= t.numberorder by tb.FBeginDate, '两个日期之间的天' /*FBeginDate FEndDate 两个日期之间的天2010-10-01 00:00:00.000 2010-10-01 00:00:00.000 2010-10-01 00:00:00.0002010-10-01 00:00:00.000 2010-10-07 00:00:00.000 2010-10-01 00:00:00.0002010-10-01 00:00:00.000 2010-10-07 00:00:00.000 2010-10-02 00:00:00.0002010-10-01 00:00:00.000 2010-10-07 00:00:00.000 2010-10-03 00:00:00.0002010-10-01 00:00:00.000 2010-10-07 00:00:00.000 2010-10-04 00:00:00.0002010-10-01 00:00:00.000 2010-10-07 00:00:00.000 2010-10-05 00:00:00.0002010-10-01 00:00:00.000 2010-10-07 00:00:00.000 2010-10-06 00:00:00.0002010-10-01 00:00:00.000 2010-10-07 00:00:00.000 2010-10-07 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-01-30 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-01-31 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-01 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-02 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-03 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-04 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-05 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-06 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-07 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-08 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-09 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-10 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-11 00:00:00.0002011-01-30 00:00:00.000 2011-02-12 00:00:00.000 2011-02-12 00:00:00.000*/
来源:https://www.cnblogs.com/lonelyxmas/p/12020063.html