jQuery: week of year script acting up

问题

A while ago I needed a script to update some content every week, and my question was answered in this forum.

Now, and I'm not a jQuery pro like you :), but the "problem" I have is that today (the moment of this post) it's week #52 but the script wasn't working, it wasn't showing the content for week #52, so I changed my HTML to week #53, and it worked.

The "problem" is that there's no week #53, so I'm afraid I'm going to have to change my HTML to continue counting for week #54, #56, #57 and so on, when those weeks don't exist.

Here's an extract of the HTML (the structure repeats over the weeks, content changes of course):

<div class="quotes-container quote-53">
 <div class="quote">Quote here...</div>
 <div class="author">&mdash; Author </div>
</div>

Script:

<script type="text/javascript">
Date.prototype.getWeek = function() {
var onejan = new Date(this.getFullYear(),0,1);
return Math.ceil((((this - onejan) / 86400000) + onejan.getDay()+1)/7);
}

jQuery(function(){  
 var today = new Date();
 var weekno = today.getWeek();
 jQuery('#quotes-wrapper').load('/common/testimonials.html div.quote-'+weekno);
});
</script>

Any idea what's going on?

Thanks a lot for any help on this.

回答1:

EDIT: The script you're using considers a "week" to be Sunday - Saturday. Since a year doesn't always start on a Sunday, it considers the first partial week to be week 1.

If you simply want 7 say periods since the first of the year, use the script below. If you want it based on Sunday, then the script you're using would be correct.

There is a week #53. It's just not a full week.

But we are in week 52. ~~I'm guessing the current script doesn't account for leap years.~~

Instead you can calculate the day of this year, and divide that by 7.

Example: http://jsfiddle.net/etTS2/2/

<script type="text/javascript">

    Date.prototype.getWeek = function() {
      var onejan = new Date(this.getFullYear(),0,1);
      var today = new Date(this.getFullYear(),this.getMonth(),this.getDate());
      var dayOfYear = ((today - onejan +1)/86400000);
      return Math.ceil(dayOfYear/7)
    };


    jQuery(function(){  
     var today = new Date();
     var weekno = today.getWeek();
     jQuery('#quotes-wrapper').load('/common/testimonials.html div.quote-'+weekno);
    });

</script>

You'll still get a result of 53 on the last day of the year (or last two days in a leap year).

EDIT: Fixed a offset of 1 on the dayOfYear.

来源：https://stackoverflow.com/questions/4539775/jquery-week-of-year-script-acting-up

标签

jquery

week-number