问题
I've made an array that is dynamically allocated by a cycle. And then a cycle that reads the numbers out of the array but i need to know the size of the array. The array is correct and fully working and has correct values in it. I defined the array like this:
int *array;
Now when i want to use this it wont work because im using a pointer:
int size = sizeof(array)/sizeof(array[0]);
How can i fix it so it works with my pointer?
回答1:
I assume you are allocating the array using one of new or malloc/calloc. In that case, you can't do this. You need to track the size in another variable or use a structure that will track the size for you.
来源：https://stackoverflow.com/questions/13594935/how-can-i-find-the-size-of-a-dynamically-allocated-array-in-c