问题
Let's say you have an std::unordered_set<std::string>
.
You have an std::string_view
object that you want to search for in the container. Problem is, you don't want to create a std::string
from your std::string_view
, as this kind of defeats the purpose of using std::string_view
in the first place.
However, it seems that std::string_view
should be usable as a key; there should be some way to compare std::string_view
and std::string
, as they both basically represent the same thing. But there isn't, not in the STL anyway.
This is an impasse, am I forced to write my own comparison object for std::string_view
and std::string
objects to use with my std::unordered_set
?
edit: This question is specific to string_view objects. The 'duplicate' question is not relevant. I received a unique answer to a unique question, as expected.
回答1:
I don't have a nice solution, but a possible workaround with minimal custom code, at the expense of increased memory usage, would be to replace your std::unordered_set<std::string>
with a std::unordered_map
that has views for keys, and strings for values (which back the views).
Unfortunately, thanks to the small string optimization, we can't rely on std::move
preserving the original address of the underlying string
's data, so something like:
std::string to_insert(...);
mymap.try_emplace(to_insert, std::move(to_insert));
isn't going to work.
Instead, it would have to be a std::unordered_map<std::string_view, std::unique_ptr<std::string>>
so we could preserve the unique address of the string's characters, making the code more like:
auto to_insert = std::make_unique<std::string>(...);
mymap.try_emplace(*to_insert, std::move(to_insert));
While insertion would be kinda ugly, simple membership testing would remain simple, since std::string
defines an implicit operator std::string_view, and std::string_view
has an implicit constructor for char*
, so membership testing remains a simple:
if (mymap.count(some_string)) { ... }
whether some_string
is a char*
, std::string_view
or std::string
.
Note: I'm not going to swear the two-liner try_emplace
-based insertion code is legal, as I'm a bit out of practice on C++, and quite leery about using a unique_ptr
in the same expression I'm move
ing from it; on g++
7.2 it seems to work, and I think the fact that the key argument to try_emplace
is constructed immediately, while the arguments to construct the value are forwarded makes this safe, but I'll acknowledge that my understanding of C++ evaluation order (or lack thereof) is not perfect. If I'm doing something illegal, not just ugly, then fixing it would require the slightly uglier (but definitely sequenced):
auto to_insert = std::make_unique<std::string>(...);
std::string_view key{*to_insert};
mymap.try_emplace(std::move(key), std::move(to_insert));
Additional note: Only the emplace
/emplace_hint
/try_emplace
functions can be safely used to update the entries in mymap
in this design. Using mymap[key] = std::move(to_insert);
or insert_or_assign
breaks if the same key is encountered twice while building the map, as the original string_view
(referencing the original string
's data) would be preserved, while the value would be replaced with the new string
, invalidating the string_view
's pointer. While insert
doesn't replace values, I believe using it would require a design more like the three-liner with try_emplace
, as making the std::pair
to insert would be unsequenced if you tried to construct both view and unique_ptr
as part of pair
construction.
来源:https://stackoverflow.com/questions/51749081/stdstring-view-and-stdstring-in-stdunordered-set