问题
Why the connect failed for ipv6 ??
# python
>>> import socket
>>> s = socket.socket(socket.AF_INET6, socket.SOCK_DGRAM)
>>> sa = ('2000::1',2000,0,0)
>>> s.connect(sa)
>>> sa = ('fe80::21b:78ff:fe30:7c6', 2000, 0, 0)
>>> s.connect(sa)
Traceback (most recent call last):
File "<stdin>", line 1, in ?
File "<string>", line 1, in connect
socket.error: (22, 'Invalid argument')
回答1:
Link-local addresses (e.g. fe80::whatever) typically require a scope id to be specified in order to work. Try
sa = ('fe80::21b:78ff:fe30:7c6%en0', 2000, 0, 0)
instead. (If the computer you're trying to connect() to is accessible via a network interface other than en0, substitute in the name of the interface where en0 is now)
来源：https://stackoverflow.com/questions/3895570/why-the-connect-failed-for-ipv6-at-python