Redefining or changing macro value

倖福魔咒の 提交于 2019-11-27 02:12:25

问题


I am currently working on an already developed project written in MFC C++ and am facing a problem with an already present macro having the definition:

#define HEIGHT_TESTS 13

I am trying to change the value from within the code but I think since its a preprocessed definition, I am unable to do that. Is there a way I could get around this problem without having to change the original macro overall (as it might affect the original functionality of the program). I am just intending to change it in one particular condition, rest everywhere else it remains the same.

Just to let everyone know, I have obviously tried out using a different macro definition with the value (17) I am intending to use, but no luck as such.

Any help would be much appreciated.


回答1:


You can undefine it and define again:

#include <iostream>

#define AAA 13

int main()
{
    #undef AAA
    #define AAA 7
    std::cout << AAA;
}

outputs: 7

Please note that statements that start with # are preprocessor directives that are taken care of before the code is even compiled. In this case, this constant AAA will be simply replaced by 7, i.e. it works just like a textual replacement with no additional checks of syntax, no type safety etc...

...which is main reason why you should avoid using macros and #defines where they can be replaced by static functions and variables :)


Why "textual replacement" ?

Look at this code:

#include <iostream>

#define AAA 13

void purePrint() {
    std::cout << AAA;
}

void redefAndPrint() {
    #undef AAA
    #define AAA 7
    std::cout << AAA;
}

int main()
{
    #undef AAA
    #define AAA 4
    purePrint();
    redefAndPrint();
    purePrint();
}

preprocessor goes line by line from the top to the bottom, doing this:

  • ah, #define AAA 13, so when I hit AAA next time, I'll put there 13
  • look, purePrint uses AAA, I'm replacing it with 13
  • wait, now they tell me to use 7, so I'll stop using 13
  • so here in redefAndPrint() I'll put there 7

transforming the given code into this one:

#include <iostream>

void purePrint() {
    std::cout << 13;
}

void redefAndPrint() {
    std::cout << 7;
}

int main()
{
    purePrint();
    redefAndPrint();
    purePrint();
}

which will output 13713 and the latest #define AAA 4 won't be used at all.




回答2:


Something like the following:

#undef HEIGHT_TESTS
#define HEIGHT_TESTS 17

// Use redefined macro

// Restore
#undef HEIGHT_TESTS
#define HEIGHT_TESTS 13



回答3:


#define A 2

#define B (A+3)

#define C (B+4)

// I want here to change the value of A - possible?

#define A (C+6)



来源:https://stackoverflow.com/questions/9274500/redefining-or-changing-macro-value

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