What's the opposite of JavaScript's Math.pow?

问题

I'm having a mental block here, and algebra not really being my thing, can you tell me how to re-write the JavaScript code below to derive the variable, c, in terms of a and b?:

a = Math.pow(b, c);
c = ?

Thanks!

回答1:

c = Math.log(a)/Math.log(b)

回答2:

Logarithms. You want the logarithm of a. B is the base, c is the exponent, so

log_b a = c

来源：https://stackoverflow.com/questions/4016213/whats-the-opposite-of-javascripts-math-pow