问题
How can I convert a wav file in java
AudioFormat targetFormat = new AudioFormat(
sourceFormat.getEncoding(),
fTargetFrameRate,
16,
sourceFormat.getChannels(),
sourceFormat.getFrameSize(),
fTargetFrameRate,
false);
in result Exception :
java.lang.IllegalArgumentException: Unsupported conversion:
ULAW 8000.0 Hz, **16 bit**, mono, 1 bytes/frame, **from** ULAW 8000.0 Hz, **8 bit**, mono, 1 bytes/frame
it is possible in java?
I need get wav file 16 bit, from 8
回答1:
Here is a method that will convert an 8-bit uLaw encoded binary file into a 16-bit WAV file using built-in Java methods.
public static void convertULawFileToWav(String filename) {
File file = new File(filename);
if (!file.exists())
return;
try {
long fileSize = file.length();
int frameSize = 160;
long numFrames = fileSize / frameSize;
AudioFormat audioFormat = new AudioFormat(Encoding.ULAW, 8000, 8, 1, frameSize, 50, true);
AudioInputStream audioInputStream = new AudioInputStream(new FileInputStream(file), audioFormat, numFrames);
AudioSystem.write(audioInputStream, Type.WAVE, new File("C:\\file.wav"));
} catch (IOException e) {
e.printStackTrace();
}
}
回答2:
Look at this one: Conversion of Audio Format it is similar to your issue suggesting looking at http://docs.oracle.com/javase/6/docs/api/javax/sound/sampled/AudioSystem.html
回答3:
You can always use FFMPEG, http://ffmpeg.org/, to do the conversion. Your Java program can call FFMPEG to do the conversion.
FFMPEG works on all OS.
来源:https://stackoverflow.com/questions/12586949/how-can-i-convert-a-wav-file-in-java