问题
I have two character variables in my dataframe start_time
and stop_time
:
start_time stop_time
<chr> <chr>
1 19:5:00 19:11:00
2 20:33:37 20:34:39
3 20:23:00 20:23:38
4 20:12:00 20:13:00
5 20:00:39 20:00:39
I would like to calculate the difference between start_time
and stop_time
in terms of minutes with dplyr. My problem is that the two variables are expressed as a character.
expected output:
diff_time
<dbl>
1 6
2 1.2
3 0.38
4 1
5 0.39
回答1:
library(dplyr)
library(lubridate)
df1 %>%
mutate(duration = seconds_to_period(as.numeric(difftime(
strptime(stop_time, "%H:%M:%S"),
strptime(start_time, "%H:%M:%S"),
units = "secs"))))
#> start_time stop_time duration
#> 1 19:5:00 19:11:00 6M 0S
#> 2 20:33:37 20:34:39 1M 2S
#> 3 20:23:00 20:23:38 38S
#> 4 20:12:00 20:13:00 1M 0S
#> 5 20:00:39 20:00:39 0S
Data:
read.table(text=" start_time stop_time
19:5:00 19:11:00
20:33:37 20:34:39
20:23:00 20:23:38
20:12:00 20:13:00
20:00:39 20:00:39", stringsAsFactors=F, header=T) -> df1
回答2:
You can use the below snippet to compute time difference and converting to time object:
as.numeric(difftime(strptime(paste("19:11:00"),"%H:%M:%S"),
strptime(paste("19:5:00"),"%H:%M:%S")))
output:
[1] 6
回答3:
You can try:
library(lubridate)
data_time <- data.frame(start_time = c("19:5:00","20:33:37","20:23:00","20:12:00","20:00:39"),
stop_time = c("19:11:00","20:34:39","20:23:38","20:13:00","20:00:39"), stringsAsFactors = FALSE)
data_time$difference <- difftime(as.POSIXct(data_time$stop_time, format = "%H:%M:%S"),
as.POSIXct(data_time$start_time, format = "%H:%M:%S"),
units = "mins")
Regards,
Alexis
来源:https://stackoverflow.com/questions/58611777/get-the-time-difference-from-time-varaibles-stored-as-character