JSON File - Java: editing/updating fields values

跟風遠走 提交于 2019-12-10 16:44:43

问题


I have some JSONObject(s) in my workflow, and the same JSONObjects are stored by writting them into a json file.

I would like an efficient way to update the json file, only fields where is needed, with the content of newer JSONObjects instances.

Eg:

On file I have

ObjectOnFile = {key1:val1, key2:val2,...}

In memory I have

ObjectInMemory = {key1:val1_newer, key2:val2_newer,...}

The update will be like:

 if (!(ObjectInMemory.get(key1).equals(ObjectOnFile.get(key1)))
       // update file field value <--- how to?

In general I would like to update the value of every key where its content is newer (different).

Actually my code is:

import org.json.JSONObject;
import com.fasterxml.jackson.databind.ObjectMapper;

ObjectMapper mapper = new ObjectMapper();
Sting key = "key1"; //whatever
JSONObject jo = new JSONObject("{key1:\"val1\", key2:\"val2\"}");
JSONObject root = mapper.readValue(new File(json_file), JSONObject.class);
JSONObject val_newer = jo.getJSONObject(key);
JSONObject val_older = root.getJSObject(key);
if(!val_newer.equals(val_older)){
   root.put(key,val_newer);
/*write back root to the json file...how? */
}

回答1:


Simply you can do like this:

import java.io.File;
import java.io.FileWriter;
import java.io.IOException;

import org.json.JSONException;
import org.json.JSONObject;

import com.fasterxml.jackson.databind.ObjectMapper;


public class Test {

    public static void main(String[] args) throws JSONException, IOException 
    {
        ObjectMapper mapper = new ObjectMapper();
        String key = "key1"; //whatever

        JSONObject jo = new JSONObject("{key1:\"val1\", key2:\"val2\"}");
        //Read from file
        JSONObject root = mapper.readValue(new File("json_file"), JSONObject.class);

        String val_newer = jo.getString(key);
        String val_older = root.getString(key);

        //Compare values
        if(!val_newer.equals(val_older))
        {
          //Update value in object
           root.put(key,val_newer);

           //Write into the file
            try (FileWriter file = new FileWriter("json_file")) 
            {
                file.write(root.toString());
                System.out.println("Successfully updated json object to file...!!");
            }
        }
    }
}



回答2:


Underscore-java can edit json files. I am the maintainer of the project. Live example

import com.github.underscore.lodash.U;

public class MyClass {
    public static void main(String args[]) {
        String json = "{\"key1\":\"val1\", \"key2\":\"val2\"}";
        java.util.Map<String, Object> object = (java.util.Map<String, Object>) U.fromJson(json);
        U.set(object, "key1", "val1_newer");
        U.set(object, "key2", "val2_newer");
        System.out.println(U.toJson(object)); 
    }
}

// {
//   "key1": "val1_newer",
//   "key2": "val2_newer"
// }


来源:https://stackoverflow.com/questions/38041893/json-file-java-editing-updating-fields-values

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